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Firdavs [7]
2 years ago
9

jordan want to double the recipe for the cake he decides to use 4 cup of sugar and 7 cups of flour. is jordan correct or incorre

ct? explain your answer
Mathematics
1 answer:
andrew11 [14]2 years ago
3 0
2 1/3 cups of sugar and 3/5 of flour that is the answer
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A person runs 1/8 mile in 1/64 hour.<br> The person's speed is (BLANK) miles per hour.
snow_tiger [21]

Answer: The person's speed is 8 miles per hour.

Step-by-step explanation:

To solve we want to convert the \frac{1}{8} and \frac{1}{64} proportionally for the number of miles per hour. We know that multiplying a fraction by its reciprocal will equal 1. So let's do that for the value of the hour.

\frac{1}{64}×\frac{64}{1} =\frac{64}{64} =1

Since we multiplied that to the number of hours we must also do that for the number of miles.

\frac{1}{8}×\frac{64}{1} =\frac{64}{8} =8

7 0
2 years ago
Pls help with this one I give brainliest thank you! Number 7
Leona [35]

Answer:

length x width x height = volume

5.5 x 2 = 11 x 3 = 33

33 ft.

hope this helps

if you have any questions you can ask!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the probability of rolling an even number first and an odd number second?
Ostrovityanka [42]

Answer: 1/4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Use the Fundamental Theorem for Line Integrals to find Z C y cos(xy)dx + (x cos(xy) − zeyz)dy − yeyzdz, where C is the curve giv
Harrizon [31]

Answer:

The Line integral is π/2.

Step-by-step explanation:

We have to find a funtion f such that its gradient is (ycos(xy), x(cos(xy)-ze^(yz), -ye^(yz)). In other words:

f_x = ycos(xy)

f_y = xcos(xy) - ze^{yz}

f_z = -ye^{yz}

we can find the value of f using integration over each separate, variable. For example, if we integrate ycos(x,y) over the x variable (assuming y and z as constants), we should obtain any function like f plus a function h(y,z). We will use the substitution method. We call u(x) = xy. The derivate of u (in respect to x) is y, hence

\int{ycos(xy)} \, dx = \int cos(u) \, du = sen(u) + C = sen(xy) + C(y,z)  

(Remember that c is treated like a constant just for the x-variable).

This means that f(x,y,z) = sen(x,y)+C(y,z). The derivate of f respect to the y-variable is xcos(xy) + d/dy (C(y,z)) = xcos(x,y) - ye^{yz}. Then, the derivate of C respect to y is -ze^{yz}. To obtain C, we can integrate that expression over the y-variable using again the substitution method, this time calling u(y) = yz, and du = zdy.

\int {-ye^{yz}} \, dy = \int {-e^{u} \, dy} = -e^u +K = -e^{yz} + K(z)

Where, again, the constant of integration depends on Z.

As a result,

f(x,y,z) = cos(xy) - e^{yz} + K(z)

if we derivate f over z, we obtain

f_z(x,y,z) = -ye^{yz} + d/dz K(z)

That should be equal to -ye^(yz), hence the derivate of K(z) is 0 and, as a consecuence, K can be any constant. We can take K = 0. We obtain, therefore, that f(x,y,z) = cos(xy) - e^(yz)

The endpoints of the curve are r(0) = (0,0,1) and r(1) = (1,π/2,0). FOr the Fundamental Theorem for Line integrals, the integral of the gradient of f over C is f(c(1)) - f(c(0)) = f((0,0,1)) - f((1,π/2,0)) = (cos(0)-0e^(0))-(cos(π/2)-π/2e⁰) = 0-(-π/2) = π/2.

3 0
3 years ago
An FM radio station broadcasts at 84 megahertz (MHz). What is the energy of each photon in Joule? Use h = 6.6 * 10 ^ (- 34) * j
iragen [17]

Answer:

E=5.544*10^{-26} J

Step-by-step explanation:

The equation for photon energy is given by:

E=hf

Where:

h=Planck\hspace{3}constant=6.6*10^{-34} \\f=Frequency\hspace{3}of\hspace{3}the\hspace{3}wave=84000000Hz

This equation telling us that the higher the frequency of the photon, the greater its energy. And the longer the photon wavelength, the lower its energy.

So, replacing the data provided in the previous equation:

E=(6.6*10^{-34} )*(84000000)=5.544*10^{-26} J

7 0
3 years ago
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