Answer:
Step-by-step explanation:
Billys mistake was when he multiplied the 80 by 12 instead of carrying the 1 from getting 160 from 80 x 2 he just put 16 and added 8 to it from 1 x 8.
Pls help i am on a timer
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We are given : Number of diagonals of a polygon = 1127 diagonals.
We know relation between number of diagonals and number of sides of the polygon.
<h3>Plugging d=1127 in above formula, we get
Multiplying both sides by 2, we get
Solving quadratic equation by factoring, we get factors
Solving for n, we get
n-49=0
n=49.
n+46=0.
n=-46.
We can't take number of sides by a negative number.
Therefore, number of sides does the polygon have 49 side.
Step-by-step explanation:
Data values:
- 50- 1
- 57- 2
- 60- 4
- 65- 3
- 72- 3
- 75- 12
- 77- 10
- 81- 6
- 83- 6
- 88- 9
- 90- 12
- 92- 12
- 95- 2
- 99- 4
- 100- 5?
Question 1: What is the mean? The standard deviation?
The mean = the average = all of the data values added together and then divided by the number of data values.
The standard deviation= the average of the squared differences from the mean.
To find standard deviation:
- Find the mean
- For each data value (number), subtract the mean and square the difference (result)
<u>Ex:</u> You have 5 data values, 600, 470, 170, 430, and 300.
The mean of these data values is
- Then work out the average of those squared differences.
Mean calculations: All of the data values added together= 50+57+57+60+60+60+60+65+65+65+72+72+72+75+75+75+75+75+75+75+75+75+75+75+75+77+77+77+77+77+77+77+77+77+77+81+81+81+81+81+81+83+83+83+83+83+83+88+88+88+88+88+88+88+88+88+90+90+90+90+90+90+90+90+90+90+90+90+92+92+92+92+92+92+92+92+92+92+92+92+95+95+99+99+99+99+100+100+100+100+100=7531
Number of data values: 91
7531/91= 82.75824175 = 82.8
The mean is 82.8.
Standard deviation:
11.34347 (sample)
11.28097 (population)
Let's go with population because this appears to be all of the grades.
11.28097 is the standard deviation (population).
Part 2: Explain how to find the standard deviation.
1. Find the mean.
2. For each data value (number), subtract the mean and square the difference (result)
3. Find the mean of those differences.
Part 3: The data values are very spread out.
Hope this helps!