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2 years ago

What is the slope of the line?

Mathematics

1 answer:

snow_tiger [21]2 years ago

7 0

Answer:

$\displaystyle 2$

Step-by-step explanation:

Starting from the y-intercept of $\displaystyle [1, 1],$ you do $\displaystyle \frac{rise}{run}$ by either moving two blocks south over one block west or two blocks north over one block east [west and south are negatives]. Doing this will give you the equation below:

$\displaystyle y = 2x + 1$

I am joyous to assist you anytime.

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Which set of ordered pairs does not represent a function? O {(-3,-9), (7,9), (9, 1), (7,3)} O {(-3,8),(-6,5), (-5, -6), (1,-6)}

kvasek [131]

Answer:

The first set of ordered pairs is not a function.

Step-by-step explanation:

The X value of 7 repeats, which means that it is not a function

7 0

2 years ago

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Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

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2 years ago

Is 226.08cm to the third power the correct response?

drek231 [11]

Surface Area of a cylinder 2(π•r²)+(2π•r)•h

So

If the diameter is 8 then the radius is 4. the height is 5.

so you have, 2(3.14•4²)+(2•3.14•4)•5

solve. PEMDAS
Parentheses & Exponents first.
2(3.14•16)+(2•3.14•4)•5
2(50.24)+(6.28•4)•5
2(50.24)+(25.12)•5
Multiplication & Division second (left to right)
100.48+125.6
Add & Subtract (left to right)
226.08cm

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3 years ago

How do you find the quadratic equation for the roots 3 and 17?

Naily [24]

The roots are 3 and 17 so the distributed equation is

(x-3)(x-17)

distribute

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x²-20x+51

I hope I've helped!

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3 years ago

Suppose a study estimated that 68% of the residents of a town (with an error range of ±8 percentage points at 95% confidence) fa

kipiarov [429]

The correct answer would be 62%

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