If you run 10 feet in 3 seconds how long does it take you to run a mile?

Fone the slope of a line that is perpendicular x = -12

Vinvika [58]

Answer:

m [slope] = 1/12

Step-by-step explanation:

If a line is perpendicular (90 degrees, forms a right angle) to another, the slope of the line must be an opposite reciprocal of the other. The opposite reciprocal of m is -1/m.

An opposite reciprocal is created by flipping the numerator and denominator, and making it negative.

Therefore, if m is -12 it's opposite reciprocal is -1/-12 = 1/12.

8 0

3 years ago

There are 30 students in Ava’s class. Nine of them belong to the Pep Club. What fraction of the class are Pep Club members?

Alex Ar [27]

Answer:

total no. of students=30

pep club students =9

:=9/30 divide by 3

;=3/10

7 0

2 years ago

The number which is a perfect square is- a) 360 b)528 c) 729 d) 677

Furkat [3]

Answer:

729.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What are the solutions of the equation f(x) = g(x), given the following:

emmainna [20.7K]

F(x) = g(x) for x = 1 and x = 3. Verify that for yourself.

7 0

3 years ago

How many 5-member chess teams can be chosen from 15 interested players? Consider only the members selected, not their board posi

ryzh [129]

Answer:

3003 number of 5-member chess teams can be chosen from 15 interested players.

Step-by-step explanation:

Given:

Number of the interested players = 15

To Find:

Number of 5-member chess teams that can be chosen = ?

Solution:

Combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula $nCr = \frac{n!}{r!(n - r)!}$

where

n represents the total number of items,

r represents the number of items being chosen at a time.

Now we have n = 15 and r = 5

Substituting the values,

$15C_5 = \frac{15!}{5!(15- 5)!}$

$15C_5 = \frac{15!}{5!(10)!}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 }{5 \times 4 \times 3 \times 2 \times 1(10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{15\times \times 14 \times 13 \times 12 \times 11}{(5 \times 4 \times 3 \times 2 \times 1)}$

$15C_5 = \frac{360360}{120}$

$15C_5 = 3003$

7 0

3 years ago