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Norma-Jean [14]
3 years ago
11

PPPPPPPPPPPLLLLLLLLLLLLLLLLZZZZZZZZZZZZZZ

Mathematics
1 answer:
svlad2 [7]3 years ago
4 0
Easiest way is if you substitute each point (x,y) into each set of equations and both points work for both equations in the system of equations, then it is the correct answer

Otherwise substitute one equation for y in the other equation:
2x + 6 = x^2 + 5x + 6
-2x - 6. -2x -6
0 = x^2 + 3x. Factor
0 = x (x + 3)
Solve: x = 0. x + 3 = 0. ——> x = -3. Substitute into one original equation to get y value for
y = 2x + 6.
y = 2(0) + 6. y = 2(-3) + 6
y = 6. y = -6 + 6 —-> y = 0
(0 , 6) And. (-3 , 0)

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telo118 [61]

Answer:

b

Step-by-step explanation:

Hope this helped! Please tell me If I'm wrong!

5 0
3 years ago
Read 2 more answers
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Alexeev081 [22]
The idea of grouping is to get the terms in groups that allow you to factor out from each group something that becomes a factor in itself, leaving two factors behind that are alike. Like this: rearrange those terms so they are in this order:
(-70y^2 - 63xy) + (90x^3 + 100yx^2).  Now out of the first set we are going to factor out a -7y, and out of the second set we are going to factor out a 10x^2. When we do this, this is what we get: -7y(10y + 9x) + 10x^2(9x + 10y). As you can see, what's inside both sets of parenthesis is the same, just in a different order. We can factor that out now, leaving (9x + 10y)(10x^2 - 7y). And that is factored by grouping.
4 0
3 years ago
A bakery has 42 donuts and 24 muffins for sale. What is the ratio of muffins to donuts
Lana71 [14]
The ration is 12 muffins to every 21 donuts
6 0
3 years ago
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she has 6 cherry candies, 3 grape candies, and 3 lime candies. If Charlotte randomly pulls one piece of candy out of the bag, wh
yKpoI14uk [10]

Answer:     \dfrac{1}{2}

Step-by-step explanation:

We know that probability for any event = \dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}

Given : Charlotte has 6 cherry candies, 3 grape candies, and 3 lime candies.

I..e Total pieces of candies she has = 6+3+3=  12

Now , If Charlotte randomly pulls one piece of candy out of the bag, what is the probability that it will be cherry is given by :-

\text{P(cherry)}=\dfrac{\text{Number of cherries}}{\text{Total candies}}\\\\=\dfrac{6}{12}\\\\=\dfrac{1}{2}

Hence, the  probability that it will be cherry is \dfrac{1}{2} .

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