A+b=(-3n+2)+(5n-7)
=(5-3n)+(2-7)
=2n-5
Came up with the same answer as the first guy
If they're integers, that means they can't be fractions (such as 15/2 and 2).
So the only couples of integers that, when multiplied, result in 15 are:
1 and 15
5 and 3.
(there are no other possibilities as both 5 and 3 are not divisible further).
The smaller of the two sums (15+1; 5+3) is 5+3=8.
The least possible sum of a and b is 8.
6x^2+14x+4
First factor out all numerical factors (=2 in this case)
2(3x^2+7x+2)
look for m,n such that m*n=3*2, m+n=7 => m=6, n=1
2(3x^2+6x + 1x+2)
Factor 3x^2+6x into 3x(x+2)
2( 3x(x+2)+1(x+2) )
factor out common factor (x+2)
2(x+2)(3x+1)
=>
6x^2+14x+4=2(x+2)(3x+1)
Answer:
A) $2.42, $2.33, $2.58
B) The best deal is 24 cupcakes for $56
Step-by-step explanation:
Given a right angle triangle
The length of the legs are 4 and 7
we will find the hypotenuse using the Pythagorean theorem
So,
![\begin{gathered} h^2=7^2+4^2=49+16=65 \\ h=\sqrt[]{65}\approx8.062 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D7%5E2%2B4%5E2%3D49%2B16%3D65%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B65%7D%5Capprox8.062%20%5Cend%7Bgathered%7D)
Rounding to the nearest tenth
So, the answer is the length of the third side = 8.1
