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konstantin123 [22]
3 years ago
5

The mean price of a home in California is much larger than the median price. Explain why this might happen.

Mathematics
1 answer:
vivado [14]3 years ago
8 0
The median price is that which is midway in the range between the cheapest and the dearest. 
<span>The mean price is the sum of all the prices divided by the number </span>
<span>For example, lets say we have seven houses in a particular road. I haven't a clue how much Californian houses cost, so I'm going to list seven arbitrary values in order of cheapest to dearest. </span>

<span>1) $100,000 </span>
<span>2) $130,000 </span>
<span>3) $130,000 </span>
<span>4) $250,000 </span>
<span>5) $310,000 </span>
<span>6) $800,000 </span>
<span>7) $900,000 </span>

<span>If the size n, of the range is odd, then the median value is at the (n+1)/2 th position in the range </span>
<span>For n = 7, (n+1)/2 = (7+1)/2 = 8/2 = 4 </span>
<span>The fourth cheapest house is priced at $250,000, which is the median </span>

<span>The sum of the cost of all seven houses is $2,620,000 </span>
<span>The mean = Sum/n </span>
<span>= $2,620,000 / 7 </span>
<span>= $374,285.71 </span>

<span>In summary </span>
<span>Median = $250,000 </span>
<span>Mean = $374,285.71 </span>

<span>The reason why the mean is much greater than the median is because of the skewed values at the top of the range. They are much higher than the others. If the prices of the sixth and seventh houses were $350,000 and $360,000 respectively, the median would still be $250,000, but now the mean would be $232,857.14 which is less than the median. </span>

<span>Unlike the median, the mean is very sensitive to the extreme points within the range. </span>

<span>If it's a single home, or all homes are the same price, then the mean and the median are equal.</span>
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liubo4ka [24]

Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
  • Mr. A purchases 4 units of Z and sells 3 units of X and 5 units of Y
  • Mr.A earns Rs6000

So, the equation would be

3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
  • Mr. B purchases 3 units of Y and sells 2 units of X and 1 units of Z
  • Mr B neither lose nor gain meaning he has made 0₹

hence,

2x   - 3y  +  z = 0

<h3>Case-3:</h3>
  • Mr. C purchases 1 units of X and sells 4 units of Y and 6 units of Z
  • Mr.C earns 13000₹

therefore,

- x    + 4y  +  6z = 13000

Thus our system of equations is

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

\implies z= \dfrac{217000}{151}

Therefore,the prices of commodities X,Y,Z are respectively approximately 1477, 1464, 1437

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OLEGan [10]
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