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attashe74 [19]
3 years ago
14

Farmer Joe sprays his crops every harvesting season. Each season he uses 230 lbs of chemicals on his farm. About 5% of the chemi

cals remains on the farm when the next season comes around. How much pounds of chemical will be on the farm after 12 harvesting seasons. Round to the nearest tenth (one decimal place).
Mathematics
1 answer:
joja [24]3 years ago
3 0

Answer:

138

Step-by-step explanation:

after one season.... 0,05 × 230 = 11,5

after 12 seasons ... 11,5 × 12 = 138

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F (5^4)m = 512, what is the value of m? 2 3 5 8
MatroZZZ [7]

Answer:

questions is wrong??

Step-by-step explanation:

5^4 is 625

4 0
3 years ago
When Devon cashed a $450 check at the bank, the teller gave him 18 bills, all $20 bills and $50 bills. Which system of equations
Ymorist [56]
You have two totals: total # of bills and total amount of $. Using x as #of 20s, and y as # of 50s, you can use the system
x+y=18
20x+50y=450
4 0
3 years ago
Read 2 more answers
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0
3 years ago
Approximate π + √70 to the nearest hundredth.<br><br> 8.37<br> 11.14<br> 11.51<br> 12.14
stellarik [79]

Answer:

The answer would be 11.51

Step-by-step explanation:

π is rougroughly 3.14

√70 = 8.37

3.14 + 8.37 = 11.51

8 0
1 year ago
Read 2 more answers
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Stolb23 [73]
$20 × 1.8 (180% in decimal form) = 36

$36 is how much you spent the 2nd

Brainliest please!
7 0
3 years ago
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