Answer:
The answer to your question is given below.
Step-by-step explanation:
1. f(x) = 5x + 1
x = – 5
f(x) = 5x + 1
f(–5) = 5(–5) + 1
f(–5) = –25 + 1
f(–5) = –24
2. f(x) = 5x + 1
x = – 1
f(x) = 5x + 1
f(–1) = 5(–1) + 1
f(–1) = –5 + 1
f(–1) = – 4
3. f(x) = 5x + 1
x = 1
f(x) = 5x + 1
f(1) = 5(1) + 1
f(1) = 5 + 1
f(1) = 6
4. f(x) = 5x + 1
x = 2
f(x) = 5x + 1
f(2) = 5(2) + 1
f(2) = 10 + 1
f(2) = 11
5. f(x) = 5x + 1
x = 2
f(x) = 5x + 1
f(3) = 5(3) + 1
f(3) = 15 + 1
f(3) = 16
Summary
x >>>>>>>> f(x)
–5 >>>>>> – 24
–1 >>>>>> – 4
1 >>>>>>>> 6
2 >>>>>>> 11
3 >>>>>>> 16
Answer:
0.3673193677
Step-by-step explanation:
Consider all options:
A.
![\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] \cdot \left[\begin{array}{cc}5&5\\-4&-4\end{array}\right] =\left[\begin{array}{cc}5\cdot 5+5\cdot (-4)&5\cdot 5+5\cdot (-4)\\-4\cdot 5+(-4)\cdot (-4)&-4\cdot 5+(-4)\cdot (-4)\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%265%5C%5C-4%26-4%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%265%5C%5C-4%26-4%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%5Ccdot%205%2B5%5Ccdot%20%28-4%29%265%5Ccdot%205%2B5%5Ccdot%20%28-4%29%5C%5C-4%5Ccdot%205%2B%28-4%29%5Ccdot%20%28-4%29%26-4%5Ccdot%205%2B%28-4%29%5Ccdot%20%28-4%29%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}5&5\\-4&-4\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D5%265%5C%5C-4%26-4%5Cend%7Barray%7D%5Cright%5D.)
This option is true.
B.
![\left[\begin{array}{cc}6&5\\5&6\end{array}\right] \cdot \left[\begin{array}{cc}6&5\\5&6\end{array}\right] =\left[\begin{array}{cc}6\cdot 6+5\cdot 5&6\cdot 5+5\cdot 6\\5\cdot 6+6\cdot 5&5\cdot 5+6\cdot 6\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%265%5C%5C5%266%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%265%5C%5C5%266%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%5Ccdot%206%2B5%5Ccdot%205%266%5Ccdot%205%2B5%5Ccdot%206%5C%5C5%5Ccdot%206%2B6%5Ccdot%205%265%5Ccdot%205%2B6%5Ccdot%206%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}61&60\\60&61\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D61%2660%5C%5C60%2661%5Cend%7Barray%7D%5Cright%5D.)
This option is false.
C.
![\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+(-0.5)\cdot (-0.5)&0.5\cdot (-0.5)+(-0.5)\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot (-0.5)+0.5\cdot 0.5\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%26-0.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%26-0.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%5Ccdot%200.5%2B%28-0.5%29%5Ccdot%20%28-0.5%29%260.5%5Ccdot%20%28-0.5%29%2B%28-0.5%29%5Ccdot%200.5%5C%5C-0.5%5Ccdot%200.5%2B0.5%5Ccdot%20%28-0.5%29%26-0.5%5Ccdot%20%28-0.5%29%2B0.5%5Ccdot%200.5%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}0.5&-0.5\\-0.5&0.5\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%26-0.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D.)
This option is true.
D.
![\left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] \cdot \left[\begin{array}{cc}0.5&0.5\\-0.5&0.5\end{array}\right] =\left[\begin{array}{cc}0.5\cdot 0.5+0.5\cdot (-0.5)&0.5\cdot 0.5+0.5\cdot 0.5\\-0.5\cdot 0.5+0.5\cdot (-0.5)&-0.5\cdot 0.5+0.5\cdot 0.5\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%260.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%260.5%5C%5C-0.5%260.5%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.5%5Ccdot%200.5%2B0.5%5Ccdot%20%28-0.5%29%260.5%5Ccdot%200.5%2B0.5%5Ccdot%200.5%5C%5C-0.5%5Ccdot%200.5%2B0.5%5Ccdot%20%28-0.5%29%26-0.5%5Ccdot%200.5%2B0.5%5Ccdot%200.5%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}0&0.5\\-0.5&0\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%260.5%5C%5C-0.5%260%5Cend%7Barray%7D%5Cright%5D.)
This option is false.
E.
![\left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] \cdot \left[\begin{array}{cc}-6&-6\\5&5\end{array}\right] =\left[\begin{array}{cc}-6\cdot (-6)+(-6)\cdot 5&-6\cdot (-6)+(-6)\cdot 5\\5\cdot (-6)+5\cdot 5&5\cdot (-6)+5\cdot 5\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%26-6%5C%5C5%265%5Cend%7Barray%7D%5Cright%5D%20%5Ccdot%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%26-6%5C%5C5%265%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-6%5Ccdot%20%28-6%29%2B%28-6%29%5Ccdot%205%26-6%5Ccdot%20%28-6%29%2B%28-6%29%5Ccdot%205%5C%5C5%5Ccdot%20%28-6%29%2B5%5Ccdot%205%265%5Ccdot%20%28-6%29%2B5%5Ccdot%205%5Cend%7Barray%7D%5Cright%5D%3D)
![=\left[\begin{array}{cc}6&6\\-5&-5\end{array}\right].](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D6%266%5C%5C-5%26-5%5Cend%7Barray%7D%5Cright%5D.)
This option is false.
Answer: correct options are A and C.
Answer:
a = 5, b = -3 and c =1
Step-by-step explanation:
The standard form of a quadratic equation is expressed as;
f(x) = ax² + bx + c
Given the expression
f(x) = 5x² = 3x - 1
f(x) = 5x² - 3x + 1
Comparing with the general formula;
ax² = 5x²
a = 5
bx = -3x
b = -3
c = 1
Hence a = 5, b = -3 and c =1
I think its 91.
NOT Guaranteed this is the Answer. Best of luck to you.
