Answer:
B. 9 Units squared
Step-by-step explanation:
Edge 2021
Answer:
<h2>The solution is -9 < x < 17.</h2>
Step-by-step explanation:
|x-4|<13.
The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.
Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.
Answer:
6.1 minutes
Step-by-step explanation:
I did it on virtual business
Answer:
3ad3 will be the answer
Step-by-step explanation:
Answer:
![a=[2q^{2}r]](https://tex.z-dn.net/?f=a%3D%5B2q%5E%7B2%7Dr%5D)
![b=[3s^{2}t]](https://tex.z-dn.net/?f=b%3D%5B3s%5E%7B2%7Dt%5D)
Step-by-step explanation:
we have

we know that
![8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}](https://tex.z-dn.net/?f=8q%5E%7B6%7Dr%5E%7B3%7D%3D%282%5E%7B3%7D%29%28q%5E%7B2%7D%29%5E%7B3%7Dr%5E%7B3%7D%3D%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D)
![27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}](https://tex.z-dn.net/?f=27s%5E%7B6%7Dt%5E%7B3%7D%3D%283%5E%7B3%7D%29%28s%5E%7B2%7D%29%5E%7B3%7Dt%5E%7B3%7D%3D%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D)
therefore
![a=[2q^{2}r]](https://tex.z-dn.net/?f=a%3D%5B2q%5E%7B2%7Dr%5D)
![b=[3s^{2}t]](https://tex.z-dn.net/?f=b%3D%5B3s%5E%7B2%7Dt%5D)
substitute

![[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})](https://tex.z-dn.net/?f=%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D%20%2B%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D%3D%28%5B2q%5E%7B2%7Dr%5D%2B%5B3s%5E%7B2%7Dt%5D%29%28%5B2q%5E%7B2%7Dr%5D%5E%7B2%7D%20-%5B2q%5E%7B2%7Dr%5D%5B3s%5E%7B2%7Dt%5D%2B%5B3s%5E%7B2%7Dt%5D%5E%7B2%7D%29)
![[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])](https://tex.z-dn.net/?f=%5B2q%5E%7B2%7Dr%5D%5E%7B3%7D%20%2B%5B3s%5E%7B2%7Dt%5D%5E%7B3%7D%3D%28%5B2q%5E%7B2%7Dr%5D%2B%5B3s%5E%7B2%7Dt%5D%29%28%5B4q%5E%7B4%7Dr%5E%7B2%7D%5D%20-6%5Bq%5E%7B2%7Dr%5D%5Bs%5E%7B2%7Dt%5D%2B%5B9s%5E%7B4%7Dt%5E%7B2%7D%5D%29)