1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AnnyKZ [126]
3 years ago
14

A horizontal force of 160 N is used to push a 50.0 kg packing crate a distance of 7.00 m on a rough horizontal surface. The acce

leration of gravity is 9.81 m/s 2 . If the crate moves with constant velocity, calculate a) the work done by the force. Answer in units of J. 005 (part 2 of 2) 10.0 points b) the coefficient of kinetic friction.
Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer: a) 1120Nm b) 0.33

Step-by-step explanation:

a) Work is said to be done when a force applied to an object causes the body to move through a distance. Mathematically,

Work done = Force × distance

To calculate the work done by the force, we will use the formula for work done

Workdone = 160 × 7

Work done = 1120Nm

b) According to friction, coefficient of kinetic friction is equal to the ratio of the moving force (Fm) to the normal reaction (R).

Normal reaction = weight of the object= mass × acceleration due to gravity

R = 50 × 9.81

R = 490.5N

Moving force Fm = 160N

Coefficient of kinetic friction = Fm/R

= 160/490.5

Coefficient of kinetic friction = 0.33

You might be interested in
A kid at the pool goes to jump from the high diving board. He climbs the stairs 3 feet, but he has to wait for the kid in front
beks73 [17]

Answer:

Probably 5 feet

Step-by-step explanation:

Since the diving board is 5 feet then it is 10 feet the it equals 5 feet if you half it

Sorry if wrong and hope this helps

7 0
3 years ago
How do I set this up
Mrac [35]

To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership.  So set the no-membership cost equal to the yearly membership cost and solve.

no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day.  So if we let d = number of days, our cost can be calculated by "7d"

a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"

Set them equal to each other and solve:


7d = 200 + 3d

4d = 200

d = 50

So you would need to attend the classes for at least 50 days to justify a yearly membership.  I hope that helps!

5 0
3 years ago
True or False: When a preimage rotates 1/4
Vitek1552 [10]

Answer:

True :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How do you write 25/20 as a percentage
earnstyle [38]
\dfrac{25}{20}=\dfrac{25\cdot5}{20\cdot5}=\dfrac{125}{100}=1\dfrac{25}{100}=1.25=1.25\cdot100\%=\boxed{125\%}\\\\\dfrac{25}{20}=\dfrac{25}{20}\cdot100\%=25\cdot5\%=\boxed{125\%}
8 0
4 years ago
The temperature is -4 degrees at 6am and rises 13 degrees by midday. What is the temperature at midday?
Mars2501 [29]

It is 9 degrees by midday

3 0
3 years ago
Read 2 more answers
Other questions:
  • At the craft store, Ronald bought a bag of purple and red marbles. He received 96 marbles in all. 48 of the marbles were purple.
    9·1 answer
  • his season, Lisa's lacrosse team has won $\frac 23$ of their home games (games played at Lisa's school), but just $\frac 25$ of
    10·1 answer
  • 11. Una escuela telesecundaria tiene una pista de carreras que mide de kilómetro.
    12·1 answer
  • Write the equation of the line. Slope = -4, passing through (- 1, 5)
    8·1 answer
  • What could be the dimensions with an area of 24 units
    6·1 answer
  • Evaluate 7 + (-3x^2) for x = 0.
    15·1 answer
  • Use the synthetic division shown to help factor the polynomial and solve the equation.
    9·2 answers
  • >......> ........... answer plz
    11·1 answer
  • (08.01)Looking at the spread of your data best fits which step of the statistical process?
    8·1 answer
  • What cross sections might you see when a plane intersects a cone that you would not see when a plane intersects a prism or a pyr
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!