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icang [17]
4 years ago
6

The preferred conformation or Cis -3-tert - buty1-1- methyl cyclohexane is the one in which: _________.

Chemistry
1 answer:
mixer [17]4 years ago
4 0

Answer:

D) both groups are equatorial.

Explanation:

To solve this question we can start by drawing the molecule in using the <u>structure of the hexagon</u>. In this structure, we have the methyl group on carbon 1 and the terbutyl group on carbon 3, additionally, if we have a cis structure both groups must have the same type of bond (in this case the wedge bond).  (See figure 1)

When we write the <u>chair structure</u>, we must keep the same structure. That is, methyl must be on carbon 1 and terbutyl on carbon 3. Also, the cis configuration must be maintained. With this in mind, we can choose the <u>equatorial configuration</u> for methyl on carbon 1 (since the position equatorial is the one that has <u>less steric impediment and more stability</u>). If this is true for carbon 1, we must place the terbutyl group on carbon 3 in the same configuration (i.e. cis). Therefore, on carbon 3 we must place the tert-butyl down on carbon 3, that is, in the <u>equatorial position</u>.  (See figure 1).

Therefore, in the chair-like structure, both groups must be in an equatorial position.

I hope it helps!

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3 years ago
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barxatty [35]

Answer:

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Explanation:

                   Percent composition of an element is the total mass of that element divided by the molecular mass of compound (or molecular mass) of which it is present in.

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3 years ago
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Verdich [7]
B
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? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







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4 years ago
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Misha Larkins [42]

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