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BARSIC [14]
3 years ago
9

PLEASE HELP ME ASAPPPPP

Mathematics
1 answer:
tester [92]3 years ago
5 0

Answer:

One solution

Step-by-step explanation:

Move variables to one side and constants to the other.

x-4y=-1

2x+8y=8 Divide this by 2

x+4y=4

Add the equations

2x=-3

x=-1.5

y=-1/8

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A pack of folders has a length of 5 inches, a width of 12 inches, and a height of 1 inch. The pack of folders will be shipped in
777dan777 [17]

Answer:

A) Each pack of folders has a volume of 60 cubic inches.

B) The box has a volume of about 720 cubic inches

D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.

Step-by-step explanation:

<em><u>Verify each statement</u></em>

<em>A) Each pack of folders has a volume of 60 cubic inches.</em>

The statement is True

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

<em>B) The box has a volume of about 720 cubic inches</em>

The statement is True

Because

The volume of the box is equal to the volume  of one pack of folders multiplied by 12

so

V=(12)60=720\ in^{3}

<em>C) If the box held 15 packs of folders, it would have a volume of about 1,200 cubic inches</em>

The statement is False

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{15}{x}\frac{packs}{in^{3}}\\ \\x=720*15/12\\ \\x=900\ in^{3}

900\ in^{3}\neq 1,200\ in^{3}

<em>D) If the box help 20 packs of folders, it would have a volume of about 1,200 cubic inches.</em>

The statement is True

Because

Applying proportion

\frac{12}{720}\frac{packs}{in^{3}}=\frac{20}{x}\frac{packs}{in^{3}}\\ \\x=720*20/12\\ \\x=1,200\ in^{3}

1,200\ in^{3}= 1,200\ in^{3}

<em>E) Each pack of folders has a volume of 24 cubic inches.</em>

The statement is False

Because

The volume of each pack of folders is equal to

V=(5)(12)(1)=60\ in^{3}

7 0
3 years ago
What is the best approximation of the area of a circle with a diameter of 17 meters? Use 3.14 to approximate pi. 53.4 m² 106.8 m
Arte-miy333 [17]
R = 17/2 =8.5 m
A = 3.14 x (8.5)^2
A = 3.14 x 72.25
A = 226.865

answer <span>226.9 m² (third choice)</span>

8 0
3 years ago
Can someone please answer this question please answer it correctly and please show work please help me I need it
I am Lyosha [343]

Answer:

the answer to this question is the number 8

5 0
3 years ago
What’s the domain and range of this graph?
avanturin [10]

Given:

The graph of a downward parabola.

To find:

The domain and range of the graph.

Solution:

Domain is the set of x-values or input values and range is the set of y-values or output values.

The graph represents a downward parabola and domain of a downward parabola is always the set of real numbers because they are defined for all real values of x.

Domain = R

Domain = (-∞,∞)

The maximum point of a downward parabola is the vertex. The range of the downward parabola is always the set of all real number which are less than or equal to the y-coordinate of the vertex.

From the graph it is clear that the vertex of the parabola is at point (5,-4). So, value of function cannot be greater than -4.

Range = All real numbers less than or equal to -4.

Range =  (-∞,-4]

Therefore, the domain of the graph is (-∞,∞) and the range of the graph is (-∞,-4].

3 0
2 years ago
Ms. Walker's class set up an online fund with a goal to raise $1,280 to go on a field trip. Ms. Walker starts the fund by deposi
madreJ [45]
What you can use for this case is a function of the potential type.
 We have then
 y = a (b) ^ x
 Where we have:
 Walker starts the fund by depositing $ 5
 a = 5
 Each week the balance of the fund is twice the balance of the previous week:
 b = 2
 The function is:
 y = 5 (2) ^ x
 The number of weeks to reach $ 1280 is 8 weeks.
 Check:
 y = 5 (2) ^ 8
 y = 1280
 Answer:
 An equation can be used to find the number of weeks, x, after which the balance of the fund will reach $ 1,280 is:
 y = 5 (2) ^ x
 The number of weeks that it takes to reach the class goal is
 8 weeks
4 0
3 years ago
Read 2 more answers
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