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Ierofanga [76]
3 years ago
15

Solve for x. x = log24

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0
Answer:
x= 1.38 (rounded)
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Is segment ST tangent to circle P1
malfutka [58]

Answer:

B . Yes

Step-by-step explanation:

Recall: a tangent of a circle is perpendicular to the radius of a circle, forming a right angle at the point of tangency.

Therefore, if segment ST is tangent to circle P, it means that m<T = 90°, and ∆PST is a right triangle.

To know if ∆PST is a right triangle, the side lengths should satisfy the Pythagorean triple rule, which is:

c² = a² + b², where,

c = longest side (hypotenuse) = 37

a = 12

b = 35

Plug in the value

37² = 12² + 35²

1,369 = 1,369 (true)

Therefore we can conclude that ∆PST is a right triangle, this implies that m<T = 90°.

Thus, segment ST is a tangent to circle P.

7 0
3 years ago
Determine whether the following graph represents a function,
eimsori [14]

Answer:

Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not have a solution.

Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.

Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation

Step-by-step explanation:

3 0
2 years ago
Help it’s homework!!!!
Airida [17]

Answer:

(3x - 3)(x + 2)

Step-by-step explanation:

3x^2 + 3x - 6

(3x^2 + 6x)(-3x - 6)

3x(x + 2) -3(x + 2)

(3x - 3)(x + 2)

3 0
3 years ago
3ab+2 x -a =2c a=2 b=3 c=7 True or False
ollegr [7]

Answer:

t

Step-by-step explanation:

8 0
2 years ago
Please help with this!!! 25 points and i'll mark you brainliest!!! Show how you got answer!!!
HACTEHA [7]

Answer:

17.9°

Step-by-step explanation:

From trigonometry:

Opposite = 14

Adjacent = x

theta = 38°

hence;

tan theta = opposite/ adjacent

tan38° = 14/x

x = 14/tan38°

x = 17.9°

6 0
2 years ago
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