Answer:
The sale price is $1
$1 is not a better price since there is a cheaper price of $0.7
Step-by-step explanation:
Original price is $2
The price now is 0.5 × $2 = $1
If the sale price was 0.35 of the original price;
It would be 0.35 × $2 = $0.7
$1 is not a better price since there is a cheaper price of $0.7
Answer:
32√5
Step-by-step explanation:
We have the right triangles PQA and PQB as well as the given right triangle QAB.
cot(PAQ) = 2/5 = QA/PQ
cot(PBQ) = 3/5 = QB/PQ
cot(PAQ) / cot(PBQ) = (2/5) / (3/5) = 2/3
cot(PAQ) / cot(PBQ) = (QA/PQ) / (QB/PQ) = QA / QB
QA / QB = 2/3
QA = (2/3) QB
QB = (3/2) QA
By the Pythagorean Theorem we have:
(QA)² + 32² = (QB)²
(QA)² + 32² = (3/2 QA)²
(QA)² + 1024 = (9/4) (QA)²
(5/4) (QA)² = 1024
(QA)² = (4/5)1024 = 4096/5
QA = 64/√5
Solve for PQ.
cot(PAQ) = QA/PQ
PQ = QA / cot(PAQ)
PQ = (64/√5) / (2/5) = 32√5
The height of the tower is 32√5.
<h3>
<u>Cookies</u></h3>
Rob: 3
Barry: 8
Kevin: 9
Let's add all of that up.
3 + 8 + 9
11 + 9
= 20 cookies total
<h3><u>
Milk</u></h3>
Rob: 2
Barry: 1
Kevin: 4
Let's add this up.
2 + 1 + 4
3 + 4
= 7 cups of milk
They had 20 cookies and 7 cups of milk before they ate.
Answer:
simplify -1-18
Step-by-step explanation:
Subtract 18 from −1
−
19
Answer:
Option c, A square matrix
Step-by-step explanation:
Given system of linear equations are
Now to find the type of matrix can be formed by using this system
of equations
From the given system of linear equations we can form a matrix
Let A be a matrix
A matrix can be written by
A=co-efficient of x of 1st linear equation co-efficient of y of 1st linear equation constant of 1st terms linear equation
co-efficient of x of 2st linear equation co-efficient of y of 2st linear equation constant of 2st terms linear equation
co-efficient of x of 3st linear equation co-efficient of y of 3st linear equation constant of 3st terms linear equation 
which is a matrix.
Therefore A can be written as
A= ![\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Blll%7D3%26-2%26-2%5C%5C7%263%2626%5C%5C-1%26-11%2646%5Cend%7Barray%7D%5Cright%5D%203%5Ctimes%203)
Matrix "A" is a 
matrix so that it has 3 rows and 3 columns
A square matrix has equal rows and equal columns
Since matrix "A" has equal rows and columns Therefore it must be a square matrix
Therefore the given system of linear equation forms a square matrix
