Find two consecutive even integers such that the sum of the larger and three times the smaller is 234
1 answer:
Represent even numbers as "2n" since each is a multiple of 2.
Represent odd numbers as "2n+1" since each is one more than an even.
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Your problem:
smaller # : 2n
larger #: 2n+2
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EQUATION:
2n+2 + 3(2n) = 234
8n = 232
n = 29
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smaller = 2*29 = 58
larger = 2n+2 = 60
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