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3 years ago

Find two consecutive even integers such that the sum of the larger and three times the smaller is 234

Mathematics

1 answer:

viva [34]3 years ago

7 0

Represent even numbers as "2n" since each is a multiple of 2.

Represent odd numbers as "2n+1" since each is one more than an even.

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Your problem:

smaller # : 2n

larger #: 2n+2

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EQUATION:

2n+2 + 3(2n) = 234

8n = 232

n = 29

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smaller = 2*29 = 58

larger = 2n+2 = 60

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The measure of one angle is 13 less than five times The measure of another angle. The sum of the measure of the two angles is 14

kodGreya [7K]

$\huge\boxed{a=\frac{229}{2};\ \ b=\frac{51}{2}}$

<em>In decimal form, a = 114.5; b = 25.5</em>

We will write this as a system of equations, where $a$ and $b$ are the two angles.

$\left \{ {{a=5b-13} \atop {a+b=140}} \right$

We will use substitution to solve this system. We know what $a$ equals, so we plug that into the second equation.

$5b-13+b=140$

Combine the like terms.

$6b-13=140$

Add $13$ on both sides.

$6b=153$

Divide both sides by $6$ .

$b=\frac{153}{6}=\boxed{\frac{51}{2}}$

Now just subtract that from $140$ .

$a=140-\frac{51}{2}=\boxed{\frac{229}{2}}$

7 0

2 years ago

The repeating decimal, 0.27..., is converted to the fraction 0.27..=3/x

brilliants [131]

I think the answer to your question is 11.11 I hope this helps

4 0

2 years ago

Read 2 more answers

Show that 2x +1 is a factor of 2x3 +5x2+4x+1 and factories completely

larisa [96]

$\text{According to the factor theorem, if f(b) = 0, then x-b is a factor of f(x).}\\\\\text{Given that,}\\\\f(x) = 2x^3 +5x^2 +4x +1 \\\\f\left(-\dfrac 12 \right) = 2\left( - \dfrac 12 \right)^3 +5 \left( - \dfrac 12 \right)^2 +4 \left( - \dfrac 12 \right) +1 \\\\\\~~~~~~~~~~~~=-2 \cdot \dfrac 18 + 5 \cdot \dfrac 14 -2 +1 \\\\\\~~~~~~~~~~~=\dfrac 54 -\dfrac14 -1\\\\\\~~~~~~~~~~~=\dfrac 44 -1 \\\\\\~~~~~~~~~~~=1-1\\\\\\~~~~~~~~~~~=0\\\\\text{So,}~ 2x +1 ~ \text{is a factor of f(x).}$

$\text{Now,}\\\\f(x) = 2x^3 +5x^2 +4x +1 \\\\~~~~~~=2x^3+x^2 +2x^2 +2x +2x+1\\\\~~~~~~=x^2(2x+1) +2x(2x+1) + (2x+1)\\\\~~~~~~=(2x+1)(x^2 +2x +1)\\\\~~~~~~=(2x+1)(x+1)^2$