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lorasvet [3.4K]
3 years ago
13

Slope of segment DE is -2 and slope of segment AC is -2 whAT is the justification for this statement?

Mathematics
1 answer:
Kryger [21]3 years ago
5 0
Answer:
slope formula

Explanation:
1- Slope of DE:
Assume point D is (x1, y1) and point E is (x2, y2). To get the slope of DE, we will substitute with the given points in the following formula:
slope of DE = (y2-y1) / (x2-x1) = -2

1- Slope of AC:
Assume point A is (x1, y1) and point C is (x2, y2). To get the slope of AC, we will substitute with the given points in the following formula:
slope of AC = (y2-y1) / (x2-x1) = -2

3- Therefore, the easiest way to get the slope of any line is by using the slope formula.

4- Note that since the two slopes are equal, this means that the two lines are parallel.

Hope this helps :)
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Hi, I am new to this website :) I'm currently taking an online trig class on De Moivre's theorem and I don't understand it at al
Vladimir [108]
De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.

For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes

[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))] 

it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.

For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)

[2^6(cos(40*6))+isin(40*6)],

[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)

And the answer is -32 -32 √3 i

Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i

7 0
3 years ago
A company has $6582 to give out in bonuses. An amount is to be given out equally to each of the 32 employees.
expeople1 [14]

A) His estimate is incorrect, since he has increased a figure to the amount that each employee would receive.

B) Rounded to the nearest dollar, each employee would receive $ 209.

Since a company has $ 6582 to give out in bonuses, and an amount is to be given out equally to each of the 32 employees, and A) a manager, Jake reasoned that since 32 goes into 64 twice, each employee will get about $ 2000 , to determine if his estimate is correct, and B) determine how much will each employee receive, rounded to the nearest whole dollar, the following calculations must be performed:

A)

  • 2000 x 32 = 64000
  • 200 x 32 = 6400

Therefore, his estimate is incorrect, since he has increased a figure to the amount that each employee would receive.

B)

  • 6582/32 = X
  • 208.68 = X

Therefore, rounded to the nearest dollar, each employee would receive $ 209.

Learn more about maths in brainly.com/question/8865479

4 0
2 years ago
Derivative of tan(2x+3) using first principle
kodGreya [7K]
f(x)=\tan(2x+3)

The derivative is given by the limit

f'(x)=\displaystyle\lim_{h\to0}\frac{f(x+h)-f(x)}h

You have

\displaystyle\lim_{h\to0}\frac{\tan(2(x+h)+3)-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan((2x+3)+2h)-\tan(2x+3)}h

Use the angle sum identity for tangent. I don't remember it off the top of my head, but I do remember the ones for (co)sine.

\tan(a+b)=\dfrac{\sin(a+b)}{\cos(a+b)}=\dfrac{\sin a\cos b+\cos a\sin b}{\cos a\cos b-\sin a\sin b}=\dfrac{\tan a+\tan b}{1-\tan a\tan b}

By this identity, you have

\tan((2x+3)+2h)=\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}

So in the limit you get

\displaystyle\lim_{h\to0}\frac{\dfrac{\tan(2x+3)+\tan2h}{1-\tan(2x+3)\tan2h}-\tan(2x+3)}h
\displaystyle\lim_{h\to0}\frac{\tan(2x+3)+\tan2h-\tan(2x+3)(1-\tan(2x+3)\tan2h)}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h+\tan^2(2x+3)\tan2h}{h(1-\tan(2x+3)\tan2h)}
\displaystyle\lim_{h\to0}\frac{\tan2h}h\times\lim_{h\to0}\frac{1+\tan^2(2x+3)}{1-\tan(2x+3)\tan2h}
\displaystyle\frac12\lim_{h\to0}\frac1{\cos2h}\times\lim_{h\to0}\frac{\sin2h}{2h}\times\lim_{h\to0}\frac{\sec^2(2x+3)}{1-\tan(2x+3)\tan2h}

The first two limits are both 1, and the single term in the last limit approaches 0 as h\to0, so you're left with

f'(x)=\dfrac12\sec^2(2x+3)

which agrees with the result you get from applying the chain rule.
7 0
3 years ago
A group of 2n people, consisting of n men and n women, are to be independently distributed among m rooms. Each woman chooses roo
vfiekz [6]

Step-by-step explanation:

Assume that

X_i = \left \{ {{1, If , Ith, room, has,exactly, 1,man, and , 1,woman } \atop {0, othewise} \right.

hence,

x = x_1 + x_2+....+x_m

now,

E(x) = E(x_1+x_2+---+x_m)\\\\E(x)=E(x_1)+E(x_2)+---+E(x_m)

attached below is the complete solution

7 0
3 years ago
Find polynomial whose zeros are 3 and -4​
horrorfan [7]

Answer:

Simplest polynomial: x²+x-12

Step-by-step explanation:

zeroes of polynomial= 3,-4

Therefore,

f(3) =0

f(-4)=0.

By factor Theorem

(x-3) and (x+4) are factors

so simplest polynomial is

(x-3)(x+4)

= x² - 3x + 4x -12

= x² + x -12

.

Hope it helps

6 0
3 years ago
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