(y+3)(y^2-3y+9)
=y(y^2-3y+9)
+3(y^2-3y+9)
=(y^3-3y^2+9y)+(3y^2-9y+27)
=y^3-3y^2+9y+3y^2-9y+27
=y^3+27
Answer:
x=3
Step-by-step explanation:
We are given the equation

This can be rewritten as

Now using the quotient rule for logarithms we can combine these two

Next we can remove the log by using an inverse operation

Now we can solve for x

Answer:
use The Explicit Formula for the Fibonacci Sequence
Step-by-step explanation:
Answer:
this makes no sense at all, what's the question?