List of the first few prime numbers greater than 3:
5, 7, 11, 13, 17, 19, 23, 29
Now find the combination that you can multiply and still have a 2 digit number:
5 x 7 = 35
5 x 11 = 55
5 x 13 = 65
5 x 17 = 85
5 x 19 = 95
5 x 23 = 115 ( 3 digit number, can't use).
7 x 5 = 35
7 x 11 = 77
7 x 13 = 91
7 x 19 = 133 ( 3 digit number, can't use).
The largest 2 digit number would be 5 x 19 = 95
Answer:
i think the answer is 7/3
Step-by-step explanation:
hope it helps hun :)
plz mark me brainliest <3
Answer:
3×2 + 3×-b
Step-by-step explanation:
Consider this solution, if it is possible, check the result:
1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8=(x+2)(x²-5x+4);
2) x²-5x+4=(x-1)(x-4), then
3) x³-3x²-6x+8=(x+2)(x-1)(x-4).
4) zeros are: -2;1;4. Other zeros are: 1 and 4.
Answer: 1;4.
Divide 636 / 12 which equals 53 ?
