What is the rate of change and initial value for the linear relation that includes the points shown in the table? x; 1,3,5,7

LUI

brilliants [131]

Answer: the seventh score is 176%,

B) modal score is 86%

Step-by-step explanation:

Mean score=83%, 7 subjects in place

Total of the scores= 405%

To find the missing score, 405% + x= 83%,

405% + x= 83% ×7 subjects

405%+ x= 581%

X= 176%

2) modal score is 86%

I hope it helps, Give me brainliest!

3 0

3 years ago

HELP FAST i'll mark you brainliest One bus is 5 miles east and 2 miles north of the bus terminal. Another bus is 3 miles west an

ipn [44]

Answer:

7 miles i think not sure cause it could also be 14 so like......

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A test has several multiple choice questions, each with 5 choices. If you guess on 4 questions, what is the probability that you

viktelen [127]

Answer:

4/20 or 1/5

Step-by-step explanation:

number of guesses/total possible outcomes (formula for this question since it is an independent event)

total possible outcomes: 4(# of questions) x 5(# of possible answers in 1 question)

total possible outcomes: 20

number of guesses: 4 x 1(there are 4 questions and you guess 1 answer for each question)

number of guesses: 4

number of guesses/total possible outcomes = 4/20 or 1/5

(I might be wrong lol, I haven't learned it in a long time)

8 0

3 years ago

The ratio of Aziz's money to Osman's money was 2:1 at first. After Aziz spent $10 ratio became 4:3. How much money did each boy

Dvinal [7]

Answer:

Aziz's money was $30

Osman's money was $15

Step-by-step explanation:

Let

x-----> Aziz's money at first

y-----> Osman's money

we know that

$\frac{x}{y}=\frac{2}{1}$

$x=2y$ ------> equation A

$\frac{x-10}{y}=\frac{4}{3}$ -----> equation B

substitute equation A in equation B and solve for y

$\frac{2y-10}{y}=\frac{4}{3}\\ \\6y-30=4y\\ \\6y-4y=30\\ \\2y=30\\ \\ y=15$

Find the value of x

$x=2(15)=30$

therefore

At first

Aziz's money was $30

Osman's money was $15

8 0

3 years ago

4.Is it sometimes, always, or never true that, if A and B both have dimensions n x n , AB=BA ? Explain.

REY [17]

Answer: Is true sometimes.

Step-by-step explanation:

I guess that here we have two matrices, A and B, that are nxn.

We can see that if those matrices can conmutate, then we can try it with some simple matrices.

$A = \left[\begin{array}{ccc}1&0\\0&-1\end{array}\right] . B = \left[\begin{array}{ccc}2&0\\1&1\end{array}\right]$

Here, we would have that:

$AB = \left[\begin{array}{ccc}2&0\\-1&-1\end{array}\right]$

$BA = \left[\begin{array}{ccc}2&0\\1&-1\end{array}\right]$

You can see that AB and BA are different, then the statement is not always true.

But it is true sometimes, if A or B are the identiti, then I*A = A*I, in this case would be true.

It is also true if A and B are diagonal matrices, let's prove it:

$A = \left[\begin{array}{ccc}a&0\\0&b\end{array}\right] , B = \left[\begin{array}{ccc}c&0\\0&d\end{array}\right]$

$AB = \left[\begin{array}{ccc}ac&0\\0&bd\end{array}\right] = BA$

5 0

4 years ago