Answer:
-12+(-10)
Step-by-step explanation:
<u>product | Sum</u>
120 -22
-12+(-10) =-22
Answer:
-12
Step-by-step explanation:
Let's replace that blank with x for now ;)
x - (-5) = -7
First, let's change that -(-5) to +5 because subtracting negatives is the same as adding.
x + 5 = -7
Subtract five from each side.
x + 5 = -7
-5 -5
x = -12
So then we change that x back to the blank and fill it in with -12.
Let me know if this helped!
Step-by-step explanation:
12x-3y+z=-7 ‖-12x+3y
z=-7-12x+3y
so you can replace z with (-7-12x+3y)
4y+3*(-7-12x+3y)=-7
4y+(-21-36x+9y)=-7
13y-21-36x=-7 ‖+21
13y-36x=14 ‖-13y
-36x=14-13y ‖*(-1)
36x=-14+13y ‖/3
12x=-14/3+13/3y
so-6x=+14/6-13/6y
(+14/6-13/6y)+2y-2*(-7-(-14/3+13/3y)+3y)=12
(+14/6-13/6y)+2y+14-28/3+26/3y-6y=12
(+14/6-13/6y)+2y+14-56/6+52/6y-6y=12
7+2.5y=12 ‖-7
2.5y=5 ‖/2.5
y=2
so
4y+3z=-7
4*2+3z=-7
8+3z=-7 ‖-8
3z=-15 ‖/3
z=-5
12x-3*2+(-5)=-7
12x-6-5=-7
12x-11=-7 ‖+11
12x=4 ‖/12
x=1/3
Answer:
The graph solution is defined in the attachment file please find it.
Step-by-step explanation:
The first line equation:
The second line equation:
Intersection points:
By adding the value of the first year (1970) into the x-value that is
Answer:
Step-by-step explanation:
Just use FOIL (first, outer, inner, last)
3(x + h)(x + h)
First --> (x)(x) = x^2
Outer --> (x)(h) = xh --> 1xh
Inner --> (h)(x) = xh -->1xh
Last --> (h)(h) = h^2
3(x^2 + 1xh + 1xh + h^2)
3(x^2 + 2xh + h^2)