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nataly862011 [7]
3 years ago
11

Which is wider 8mm or 5/16in

Mathematics
2 answers:
Kipish [7]3 years ago
8 0
5/16 inches, because if you look on a ruler, 5/16 inches is much longer
zepelin [54]3 years ago
5 0
The answer is that 5/16 is longer.Hope this helps!!!!!!!!! :D
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I need to find a but I don’t know how to, could you please explain
Dafna1 [17]

Answer:

87

Step-by-step explanation:

Given is a figure of cyclic quadrilateral.

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Therefore,

z° + 93° = 180°

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I need help ,, i don't understand !<br>​
otez555 [7]

Answer: B

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7 0
3 years ago
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evablogger [386]

Answer:

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∛6t^2= (6t^2)^1/3=

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8 0
3 years ago
Kilgore's Deli is a small delicatessen located near a major university. Kilgore does a large walk-in carry-out lunch business. T
AfilCa [17]

Answer:

z (max)  =  6.15

x₁  =  1       x₂ =  3    x₃  =  6

Amount of beef leftover     2 lb

Amount of onions leftover   0

Amount of  Special Sauce leftover 61

Amount of Hot Sauce leftover   9

Step-by-step explanation:

Ingredients              Beef      Onions    Special S   Hot S      Profit  

Wimpy  (x₁)                   1              2                5              0             0.6

Dial 911 (x₂)                   1              2                2              5             0.55

Fire Bowl (x₃)                1.5           2                3              6             0.65

Available                       15            20             90             60        

Objective Function z:

z  =  0.6*x₁  +  0.55*x₂  +  0.65*x₃      to maximize

Subject to:

1) Quantity of beef : 15

x₁  +  x₂  + 1.5*x₃  ≤  15

2) Quantity of onions:  20

2*x₁  +  2*x₂  +  2*x₃  ≤  20

3) Quantity of Special sauce: 90

5*x₁  + 2*x₂  + 3*x₃  ≤  90

4) Quantity of hot sauce:  60

0*x₁   + 5*x₂  + 6*x₃  ≤  60

5) Condition: The number of servings for Fire Bowl must be at least 10% of the total number of servings for all three luncheon chili specials.

x₃  ≥  0.1 ( x₁  +  x₂   +  x₃ )     or    x₃    ≥   0.1*x₁  +  0.1 *x₂  + 0.1*x₃

x₃   -   0.1*x₁  -  0.1 *x₂  - 0.1*x₃   ≥  0

-   0.1*x₁  -  0.1 *x₂   +    0.9 *x₃   ≥  0

6)Condition: The number of servings for Fire Bowl, however, cannot exceed the number of Dial 911 by more than 3.

x₃  -  x₂  ≤  3

7)the available number of servings for Dial 911 must be at least 2.

x₂  ≥  2

General constraints:

x₁  ≥   0           x₃   ≥ 0    all integers

With on-line solver solution  is:

z (max)  =  6.15

x₁  =  1       x₂ =  3    x₃  =  6

By sbstitution on the constraints

1)   x₁  +  x₂  + 1.5*x₃  ≤  15               1 + 3 + 9  = 13

Amount of beef leftover     2 lb

2)  2*x₁  +  2*x₂  +  2*x₃  ≤  20          2 + 6  + 12 = 20

Amount of onions leftover   0

3) 5*x₁  + 2*x₂  + 3*x₃  ≤  90             5  + 6  + 18 = 29

Amount of  Special Sauce leftover 61

4)0*x₁   + 5*x₂  + 6*x₃  ≤  60             15  +  36  = 51

Amount of Hot Sauce leftover   9

3 0
3 years ago
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