Answer:
Small rooms reserved = 8
Large rooms = 6
Step-by-step explanation:
Let the number of large rooms be x
Evelyn booked 2 more small rooms than the larger rooms.
Therefore the number of small rooms would be x+2.
Given each large room can accommodate 5 people.Therefore the total number of people in large rooms are 5x.
Given each small room can hold 3 people. Therefore the total number of people in large rooms are 3(x+2)
Total number of people accommodated = 54
Total number of guests = total guests in small rooms + total guests in large rooms
No of large rooms = x = 6
No of small rooms = (x+2) = (6+2) = 8
On a basic parallelogram, opposite sides are parallel, diagonals bisect each other and, consecutive angles are supplementary. However on a parallelogram diagonals aren't congruent.
So the answer is D
Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
2.50 = .15x + .7
-.7 - .7
1.8 = .15x
12 = x
7 more dimes so 12 nickels and 19 dimes