x = perimeter
x<156
length = 66
so, in order to calculate perimeter you need to add two lengths and two widths
so
156 (perimeter) - 2 (66) = two widths
156 - 132 = 24 (remember this number is two widths added together)
so 24 twice the width SO 12 would be the number that the width can't be larger than
the width has to be less than 12
w < 12
Answer / Step-by-step explanation:
It should be noted that the question is incomplete due to the fact that the diagram has not been provided. However, the diagram has been complementing the question has been provided below.
To solve the question in the narrative, we recall the equation used in solving for displacement:
Thus, δₙₐ = Σ pL/AE
Where:
P is applied axial force.
E is the young's modulus of elasticity.
A is the area of cross-section.
L is length of the bar
Therefore, -8 (80) ÷ π/4 ( 0.85)² (18) (10³) + 2(150) ÷ π/4 (1.1)² (18) (10³) + 6(100) ÷ π/4 (0.45)² (18) (10³)
Solving further,
we have,
-8 (80) ÷ 0.7853( 0.85)² (18) (10³) + 2(150) ÷ 0.7853(1.1)² (18) (10³) + 6(100) ÷ 0.7853 (0.45)² (18) (10³)
= -640÷ 0.7853( 0.85)² (18) (10³) + 300 ÷ 0.7853(1.1)² (18) (10³) + 600 ÷ 0.7853 (0.45)² (18) (10³)
Solving further, we arrive at 0.111 in answer.
The positive sign indicates that end A moves away from end D.
5/2 is the answer.
Have a nive day!
Answer:
a and c
Step-by-step explanation: