The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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Answer:
It is a season in which fish reproduce.
Explanation:
Piracema is not name of the fish, its the name given to the period of the year when fish reproduce within the Paraguay River. The season of reproduction started from October till March, during this period the fish swim upstream to lay their eggs and reproduce. Thus the season is critical for the maintenance of fish populations in the waters of the rivers and lakes. Brazilian states prohibit fishing during this period in order to maintain fish population in the river.
Explanation:
I don't think he provided all the information or some words are misspelled
