Answer:
y = 6cos(π/2)t
Step-by-step explanation:
Given in the question that,
in a simple harmonic motion in which
at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.
And,
the period is given as 4 sec
We know that model equation of simple harmonic motion is
<h3>y = a. cosb(t + c) + d</h3>
here,
a is amplitude
c is Horizontal shift or phase shift
d is Vertical shift
<h3>Step1</h3><h3>Find b</h3>
Period = 2 π / b
4 = 2π / b
b = 2π/4
b = 1π/2
<h3>Step2</h3><h3>Find shifts</h3>
Horizontal and vertical shifts are 0.
So, c = 0 and d = 0
<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>
y = 6cos π/2 (t + 0) + 0
y = 6cos(π/2)t
You need to find out if 57 can be divided evenly by a number other than 1 and 57.
57 is odd, so it is not divisible by 2.
The digits of 57 are 5 and 7. Add 5 + 7 to get 12. Since 12 is divisible by 3 (12/3 = 4), then 57 is also divisible by 3.
57/3 = 19
19 is a prime number, so the only factors of 57 are 1, 3, 19, 57.
57 rows can be divided into 19 sections of 3 rows each or 3 sections of 19 rows each.
Answer:
110
Step-by-step explanation:
Divide 176 by 8 to get 22 and then multiply 22 by 5 to get 110
Answer:
(3,0) (1,-2)
Step-by-step explanation:
0=3-3 0=0
-2=1-3 -2=-2
Here: Fraction = 3/5
Let, original fraction (before simplifying) = 3x/5x
Then, 3x + 5x = 40
8x = 40
x = 40/8
x = 5
So, 3x = 3(5) = 15 & 5(5) = 25
In short, Your Answer would be 15/25
Hope this helps!
