2 years ago

Find the area of a rectangle with side lengths 5/8 ft and 1/3 ft.

Mathematics

1 answer:

forsale [732]2 years ago

5 0

Answer:

$\frac{5}{24} ft^{2}$

Step-by-step explanation:

$\frac{5}{24} ft^{2}$

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Step-by-step explanation:

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strojnjashka [21]

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "

According to Pythagoras theorem,

$\boxed{ \large \boxed{h {}^{2} = {b}^{2} + p{}^{2} }}$

note :

p = perpendicular / opposite side
b = base / adjacent side
h = hypotenuse

let's solve for " y² " first ( square of other missing side )

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$➢ \: \: {y}^{2} = 64 + 9$

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now let's solve for " x " , by using pythagorous theorem

$➢ \: \: {x}^{2} = {y}^{2} + {6}^{2}$

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