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Kamila [148]
3 years ago
14

A bulletin board has a perimeter of 200 inches. Which expression expresses the area A(w) of the bulletin board as a function of

its width, w?
Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0

Answer:

area A(w) of the bulletin board as a function of its width, w =[100-w]*w= 100w-w^{2}

Step-by-step explanation:

  • let, the shape of the bulletin board is a rectangle,
  • then the perimeter of it = sum of all sides

= 2[length+width] = 2[l+w]

(let l: length, w : width )

  • so, 200 = 2[l+w]

100= l+w ( dividing both the sides by 2)

so, l= 100-w

  • area = length*width=l*w=[100-w]*w
  • therefore,area A(w) of the bulletin board as a function of its width, w =[100-w]*w= 100w-w^{2}
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The estimate would be 1200.

We will set up a proportion for this.  10 out of 60 of the sample were tagged, so that is the first ratio.  The 200 that were tagged would be in the numerator of the second ratio (10 was the portion tagged, and 200 is the portion tagged, so they both go on top).  We do not know the total number so we use a variable:

10/60 = x/200

Cross multiply:

10*x = 60*200
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Divide both sides by 10:
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if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length
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5. Suppose that a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organ
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Answer:

Probability that the sample proportion will be greater than 0.5 is 0.8133.

Step-by-step explanation:

We are given that the a particular candidate for public office is in fact favored by p = 48% of all registered voters. A polling organization is about to take a simple random sample of voters and will use the sample proportion to estimate p.

Suppose that the polling organization takes a simple random sample of 500 voters.

<em>Let </em>\hat p<em> = sample proportion</em>

The z-score probability distribution for sample proportion is given by;

               Z = \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion

           p = population proportion = 48%

           n = sample of voters = 500

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample proportion will be greater than 0.5 is given by = P( \hat p > 0.50)

  P( \hat p > 0.50) = P( \frac{ \hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < \frac{0.50-0.48}{\sqrt{\frac{0.50(1-0.50)}{500} } } ) = P(Z < 0.89) = 0.8133

<em>Now, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 0.89 in the z table which has an area of 0.8133.</em>

Therefore, probability that the sample proportion will be greater than 0.50 is 0.8133.

6 0
3 years ago
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