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Makovka662 [10]
4 years ago
7

Como colorear 4 enteros

Mathematics
1 answer:
Delicious77 [7]4 years ago
4 0

Answer:  

Esta no es una pregunta, pero si la reformula, podría ayudar

Step-by-step explanation:

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Which stamens is correct ?
Vilka [71]

Answer:

i think stament 2 is correct

Step-by-step explanation:

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3 years ago
Jordan found 6×8 by breaking apart the six into 5+ one which of the following correctly shows the next step in finding the resul
Oduvanchick [21]
Can u take a pic to see in what u need help
8 0
3 years ago
Help ASAP please, 10 points if you do
Andre45 [30]
I would say B.

Your starting term is 10, so that is your a1 value. Each time you add 4 to the number before, like 10+4=14 and so on, so that would mean (a-1)+4.
7 0
3 years ago
Read 2 more answers
Help please, 30 points reward, i literally have no clue
Brums [2.3K]

The explanation for this is one of my favorite pieces of mathematical reasoning. First, let's thing about distance; what's the shortest distance between two points? <em>A straight line</em>. If we just drew a straight line between A and B, though, we'd be missing a crucial element of the original problem: we also need to pass through a point on the line (the "river"). Here's where the mathemagic comes in.

If we take the point B and <em>reflect it over the line</em>, creating the point B' (see picture 1), we can draw a line straight from A to B' that passes through a point on the line. Notice the symmetry here; the distance from the intersection point to B' is<em> the same as its distance to B</em>. So, if we reflect that segment back up, we'll have a path to B, and because it came from of the line segment AB', we know that it's <em>the shortest possible distance that includes a point on the line</em>.

If we apply this same process to our picture, we see that the line segment AB' crosses the line \ell at the point (1, 1)

6 0
4 years ago
D is the planar region bounded by y = 0, y = x² and x = 1. Find the value of the integral below.​
MissTica

\displaystyle \iint_D x e^y \, dA = \int_0^1 \int_0^{x^2} x e^y \, dy \,dx \\\\ ~~~~~~~~ = \int_0^1 x (e^{x^2} - 1)\, dx \\\\ ~~~~~~~~ = \frac12 \int_0^1 e^u \, du - \int_0^1 x \,dx = \boxed{\frac{e - 2}2}

8 0
2 years ago
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