220= 45*x. I hope you are satisfied with my answer.
Gina surveyed students about their lunch time preference. Out of 50 students, 20 prefer eating lunch at 11:00am, 15 prefer eating at 11:15a.m., 10 prefer eating at 11:30a.m. , and 5 have no preference. Based on the information, what is the probability that a student chosen at random has no lunch time preference?
Answer:
f(g(1))=1/3
g(f(2))=1
Step-by-step explanation:
For f(g(1)) plug the 1 in the x in thefunction of g, and plug g in the x in the function f.
Do the same thing for g(f(2)) using the number 2
#2 the pattern is by 5
#4 the pattern is by 7
