We are given an equation with an unknown variable x. We can find the value of x by dividing both sides by 1.76, as this will leave only x on the right hand side of the equation and its value on the left hand side, as shown below:
Thus solving the given equation, we get x =4.16, rounded of to nearest hundredth.
Answer:
Area = 22.3 m^2
Perimeter 27.4 m^2
Step-by-step explanation:
Perimeter = __ m
Area __ m^2
The area of the triangle is about 4.2,
The area of the square is 4,
The area of the semicircle is 14.1,
14.1 + 4.2 + 4 = 22.3
Area = 22.3 m^2
9.4 + 6 + 4 + 4 + 4 = 27.4
Perimeter = 27.4 m^2
Therefore the area of the shape is about 22.3 m^2 and the perimeter is about 27.4 m^2.
Answer:
Step-by-step explanation:
We are give the following in the question:
Dimensions of rectangle:
Length , l =
Width of rectangle, w =
Area of rectangle = 125 square cm.
Area of rectangle =
Putting values, we get,
is the required equation.
Could i see a picture please
Use a^2 + b^2 = c^2
the triangle must be isosceles because the two angles are the same
1.2^2 + 1.2^2 = x^2
1.44 + 1.44 = x^2
2.88 = x^2
x=6√2/5
or
x ≈1.69706
