All categories

3 years ago

Find the value for y.

Mathematics

2 answers:

Elena L [17]3 years ago

8 0

The answer is 112 degrees

good luck

melamori03 [73]3 years ago

6 0

Answer:

I got 112 degrees for my answer.

Step-by-step explanation:

You might be interested in

I don’t know what to do please help

Lesechka [4]

Answer:

f(2)=0

Step-by-step explanation:

You plug in 2 for any X's in the equation

f(2)=2^2-4

4 0

2 years ago

Read 2 more answers

A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.

mario62 [17]

Answer:

$(x-7)^2+(y-5)^2=1$

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

Center of the circle:

The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

$(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)$

$(x_m, y_m) = (7,5)$

This is the center coordinate of our circle.

Radius:

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}$

$r = \sqrt{(6-7)^2+(5-5)^2}$

$r = \sqrt{1^2}$

$r = 1$

Equation of the circle:

The equation is written as:

$(x-a)^2+(y-b)^2=r^2$

here, (a,b) are the center points of the circle

in our case this is $(a,b)=(x_m,y_m)=(7,5)$

and r = 1

$(x-7)^2+(y-5)^2=1^2$

$(x-7)^2+(y-5)^2=1$

This is the equation of the circle!

3 0

3 years ago

Simple math

Artist 52 [7]

Paper clip. a paper clip would be about the size of her thumb so she would be able to use. for example, her thumb is 2 paperclips long. therefore the answer would be paperclip.
give me brainliest :D

3 0

3 years ago

What did I do wrong on the number of votes one of them is wrong or a couple are wrong pleaasseeee tell me!!!!

DiKsa [7]

I don't see any wrong

4 0

3 years ago

Given: MNFD is a trapezoid.

Rama09 [41]

A trapezoid with legs MN = FD is an isosceles trapezoid.
An isosceles trapezoid has diagonals that are congruent, therefore: MF = ND.
A quadrilateral with diagonals congruent and perpendicular is a square.
In a square, the height coincides with the side.
The area of a square is given by A = s²
Therefore, the area of MNFD is h²

6 0

3 years ago