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8_murik_8 [283]
3 years ago
12

What is the area of the figure?

Mathematics
1 answer:
Archy [21]3 years ago
6 0

Answer:

The total area= area of the rectangle+ area of triangle

Area of rectangle =base *height =5*(1/3)=5/3

Area of triangle=0.5 *base* height = 3.66*0.5*2= 3.66

The total area= 3.66+5/3 =5.33 feet^2

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Find the solution of the system of equations.<br> -7x - 4y = -44<br> 7x - 3y = 16
Y_Kistochka [10]

Answer: 7040/1767

Step-by-step explanation:

6 0
2 years ago
A factory has three machines making energy drinks. When all three machines are running, 520 drinks are made each hour. When only
Vinil7 [7]

Let A, B and C be the amount machines A, B and C, respectively, produce each hour alone.

With all three machines together produce 520 drinks each hour, we know that the addition of the amount that each produces each hour is equal to 520, that is.

A+B+C=520_{}

Now, similarly, machines A and B produce together 320 drinks each hour, so the sum of the amounts A and B produce each hour is equal to 320, so:

A+B=320

If machine C produce 30 more drinks than B each hour, than the amount of B plus 30 will be the amount of C:

C=B+30

So, we got the system of equations:

\begin{gathered} A+B+C=520 \\ A+B=320 \\ C=B+30 \end{gathered}

To solve, notice that A + B is known, because of the second equation, so we can substitute A + B by 320 in the first equation:

\begin{gathered} (A+B)+C=520 \\ 320+C=520 \\ C=520-320=200 \end{gathered}

Now, we can substitute C into the third equation and solve for B:

\begin{gathered} C=B+30 \\ 200=B+30 \\ B+30=200 \\ B=200-30=170 \end{gathered}

And, finally, we can substitute B into the second equation and solve for A:

\begin{gathered} A+B=320 \\ A+170=320 \\ A=320-170=150 \end{gathered}

Answers:

First box:

A+B+C=520

Second box:

A+B=320

Third box:

C=B+30

Fourth box:

150

3 0
1 year ago
HELP ASAP, WILL THANK AND MARK BRAINLIEST
Anastasy [175]
1. 3g+6/h =
   3(5) + 6/7 =
   15 +6/7=
   21/7=
  <span> 3

</span>
<span>Simplify each expression

1. √25/81 =
    5/81
</span>
5 0
4 years ago
What is the measurement in degrees and radians for the rotation of counter-clockwise 5/3
irga5000 [103]
I am assuming 5/3 refers to 5/3rds of a full revolution.
radians is easier for now so I'll do that first. on full revolution = 2π radians, but you have 1 and 2/3rds revolutions, so that is 2π+2π*(2/3)=10π/3 radian turn
to convert from radians to degrees multiply the radians by 180/π, so (10π/3)*(180/π) => 600degrees
Final answer:
5/3 turn is 600 degrees and 10π/3 radians
Hope I helped :)
5 0
4 years ago
The equation of the line through point (- 4, 0) and parallel to the y-axis is
riadik2000 [5.3K]
The gradient of y axis is zero. Since the line is parallel to y axis, its gradient is also zero. This
y=mx+c
Where m is the gradient;
y=(0)x+c
y=c
Replacing for y and x;
0=0(-4)+c
c=0
7 0
3 years ago
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