The other parallel side is 44 m
Step-by-step explanation:
Let us revise the formula of the area of a trapezium
, where
- and are its parallel bases
- h is its height (The distance between the two parallel bases)
∵ The area of a trapezium is shaped field is 480 m²
∴ A = 480 m²
∵ The distance between two parallel sides is 15 m
∴ h = 15 m
∵ One of the parallel side is 20 m
∴ = 20 m
We need to find
Substitute all these value in the rule of the area below
∵
∴
- Multiply the two sides by 2
∴
- Divide both sides by 15
∴
- Subtract 20 from both sides
∴
The other parallel side is 44 m
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You can learn more about trapezium in brainly.com/question/7287774
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A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:
Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1
We know that the time is always positive, therefore
when the stuntman is 10m above the ground.
height
Put height value in equation 1
Therefore ,time interval of camera film him is
Answer: equations 1,3,4 and 5 stated has solutions.
Step-by-step explanation:
From the question, (x + 5) + 5 = (x + 5) + 5
The equations that represent the situation are:
1. x + 5 = (5 − x) − 5 :which has one solution
2. x + 5 = (x + 5) − 5 : many solutions
3. x + 5 = (x + 5) − 5: no solution
4. x + 5 = (5 − x) − 5 : many solutions
5. (x + 5) + 5 = (x + 5) + 5: many solutions
Equation 2 has no solution. While the other equations have one and more than one solutions.
Step-by-step explanation:
We know that the length of the diagonals will be more than the side.
Lets suppose the quadrilateral is a rectangle, with sides 6 and 4.
The length of a diagonal is:
√(6*6)+(4*4)
√36+16
√52
7.21(rounded off to 3 sig. fig.)
So, 6+4+6+4<2(7.21+7.21)
20< 2*14.42
20<28.84, which is true.
:)
2 + 2 = 4
4 + 3 = 7
7 + 4 = 11
11 + 5 = 16
Every next term is by one greater then the incremented previous term.
Hope this helps.