If the diagonals of a parallelogram are congruent, then the parallelogram is a rectangle.
so QS is congruent to TR satisfies this rule
so option number three is correct
Answer:
3
Step-by-step explanation:
find value at 12 =12
find value at 10 = 6
so it changes + 6 for a change from 10 to 12
6/2 = 3
Answer: 0.63 repeating
Step-by-step explanation:
Alrighty! So, we're going to be dividing 7/11. First off, we know that 11 cannot go into 7, so we will add a decimal point to the 7. We now have 7.0 (aka 70) divided by 11.Don't forget to add the decimal on top! How many times does 11 go into seventy? Six times. So, now we put the six on top. Six times 11 equals 66, so now we're doing to subtract 66 from 70. Your answer should be 4. And because we haven't gotten our final answer yet, we will have to add another a 0 to 7.0 (now 7.00) and add the 0 down to 4 aswell (now 40) Now, how many times does 11 goes into 40? 3. So add the 3 on top. 11x3 equals 33, so now we're going to subtract 33 from 40. You should get 7. Like the last time, since we haven't gotten a final answer, we're going to add another 0 to 7.00 (now 7.000) and bring a 0 down. You should now have 70.
Just to help you save some time, if you repeat this process, you will get a repeating decimal ( 0.63636363636363636363636363...) So, your final answer is 0.63 repeating. (Add a line above the 63 to indicate its repeating)
Sorry if this is kinda complicated, I tried my best to explain it!
^_^
<u>*Let me know if you have any questions!</u>
Part (a)
<h3>Answer: 0</h3>
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Explanation:
Point P is part of 3 planes or faces of this triangular prism:
- plane PEF (the front slanted plane)
- plane PEH (the left triangular face)
- plane PHG (the back rectangular wall)
Notice how each three letter sequence involves "P", though this isn't technically always necessary. I did so to emphasize how point P is involved with these planes.
Each of the three planes mentioned do not involve line FG
- Plane PEF only deals with point F
- Plane PEH doesn't have any of F or G involved
- plane PHG only involves G
So there are no planes that contain line FG and point P.
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Part (b)
<h3>Answer: 0</h3>
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Explanation:
It's the same idea as part (a) earlier. The planes involving point G are
- plane GQF (triangular face on the right)
- plane GFE (bottom rectangular floor)
- plane GHP (back rectangular wall)
None of these planes have line EP going through them.
As an alternative, we could reverse things and focus on all of the planes connected to line EP. Those 2 planes are
- plane PEH (triangular face on the left)
- plane PEF (front slanted rectangular face)
None of these planes have point G located in them.
A sum of money paid as compensation
