Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
4/pi=w-6/pi
<u>4</u><u> </u><u> </u><u> </u>=<u> </u><u>w</u><u>-</u><u>6</u>
<u>Pi</u><u> </u><u> </u><u> </u><u> </u><u> </u><u>pi</u>
Cross mutiply
Pi(w-6)=4(pi)
Wpi - 6pi =4pi
Collect like terms
Wpi=4pi + 6pi
Wpi =10pi
<u>Divide</u><u> </u><u>both</u><u> </u><u>sides</u><u> </u><u>by</u><u> </u><u>pi</u>
<u>Wpi</u><u> </u>= <u>10pi</u>
Pi pi
W = 10
Answer:
Step-by-step explanation:
8 (x -3) +7 = 2x (4 -17)
8(x -3) +7 = 2x (-13) here was the error because the had 13 that is incorrect
8x -24 +7 = -26x
8x -17 = -26x
-17 = -26x -8x
-17 = -34x
-17/-34 = x
1/2 =x
Answer:

Step-by-step explanation:
We know i×i=i^2 which has value of -1.
We will multiply numerator and denominator by i so the denominator will no longer contain imaginary part(s).
Also multiplying by i/i does not change the value of the fraction because i/i=1.
Numerator × i gives (-5+i)i=-5i+i^2=-5i-1
=-1-5i.
Denominator × i gives (2i)i=2i^2=-2.
So the simplified version of this fraction given is:

The last simplification come from me multiplying fraction by -1/-1.
Answer:
Step-by-step explanation:
with what