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vova2212 [387]
4 years ago
6

A triangle has a base 3cm greater than 5 times its height. what is the area if the triangle when it's height is 6cm

Mathematics
2 answers:
Xelga [282]4 years ago
7 0

Let

b--------> the length of the base of a triangle

h--------> the length of the height of a triangle

we know that

The area of a triangle is equal to

A=\frac{1}{2}* b*h

b=3+5h ------> equation 1

if the height is h=6\ cm

then

<u>Find the value of b</u>

substitute in the equation 1

b=3+5*6=33\ cm

<u>Find the area of the triangle</u>

A=\frac{1}{2}* 33*6

A=99\ cm^{2}

therefore

<u>the answer is</u>

the area of the triangle is equal to 99\ cm^{2}

Digiron [165]4 years ago
3 0
99cm.

5x6=30+3=33
33x6=198
198/2=99
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Write two polynomials whose sum is x to the second power and whose difference is 1
Alex777 [14]

Answer:

Therefore, the  first polynomial is:

Z=\frac{1}{2}x^2+\frac{1}{2}\\

the second polynomial is:

Y=\frac{1}{2}x^2-\frac{1}{2}\\

Step-by-step explanation:

We assume that: Z is first polynomial and Y is second polynomial.

Therefore, we have

Z+Y=x^2\\\\Z-Y=1\\\\\implies Z+Y+Z-Y=x^2+1\\\\2Z=x^2+1\\\\Z=\frac{1}{2}x^2+\frac{1}{2}\\

now, we get

\implies Z+Y-Z+Y=x^2-1\\\\2Y=x^2-1\\\\Y=\frac{1}{2}x^2 -\frac{1}{2}

Therefore, the  first polynomial is:

Z=\frac{1}{2}x^2+\frac{1}{2}\\

the second polynomial is:

Y=\frac{1}{2}x^2-\frac{1}{2}\\

6 0
3 years ago
Elizabeth has $10, $5, and $1 bills worth $101. she has five more five dollar bills than ten dollar bills and 4 times more 1 dol
vesna_86 [32]

Let x be number of $10 dollar bills

Let y be number of $5 dollar bills

Let z be number of $1 dollar bills

From the question, we can come up with three equations (so we can find the values of x, y & z) :

  • 10x + 5y + z = 101
  • y - x = 5
  • z = 4x

The first equation comes from finding the total money Elizabeth has, which is $101.

The second equation comes from value of y (number of $5 bills) is more than value of x (number of $10 bills) by 5 dollars.

The third equation comes from the value of z (number of $1 bills) being 4 times more than the value of x (number of $10 bills).

Now, we will begin to find the value of x, y & z.

From the first equation,

10x + 5y + z = 101

Substitute the third equation (z = 4x) into z:

10x + 5y + 4x = 101

Simplify this and you get,

14x + 5y = 101

Now, we use the second equation. The second equation is y - x = 5. If we try to make y as the subject, it becomes y = 5 + x.

Now, substitute this into the value of y of the last working we did:

14x + 5(5+x) = 101

Simplify that and it becomes:

x = 4

Then, substitute this value of x into the second and third equations to find y and z.

y - x = 5

y - 4 = 5

y = 9

z = 4x

z = 4(4)

z = 16

Finally, let's check these answers by substituting them into the first equation to try and see if the total value is <em>really</em> $101.

10x + 5y + z = 10(4) + 5(9) + 16

10x + 5y + z = 40 + 45 + 16

10x + 5y + z = 101

Thus, our answers are correct. Elizabeth has FOUR $10 bills, NINE $5 bills and SIXTEEN $1 bills.

6 0
3 years ago
Read 2 more answers
TEST QUESTION PLS HELP!
Marat540 [252]
It should be f since you can subtract from both sides and divide by negative 1
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Help please............
tigry1 [53]

Answer:

\tan(J) =\frac{5\sqrt{66}}{66}

Step-by-step explanation:

\tan(J) =\frac{5}{\sqrt{66}}

\tan(J) =\frac{5}{\sqrt{66}} \times \frac{\sqrt{66}}{\sqrt{66}}

\tan(J) =\frac{5\sqrt{66}}{\sqrt{66}\times\sqrt{66} }

\tan(J) =\frac{5\sqrt{66}}{66}

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3 years ago
Find two numbers thar multtiply to give 19
AVprozaik [17]
19 is a prime number so you can multiply 1*19 ,
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6 0
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