A triangle has a base 3cm greater than 5 times its height. what is the area if the triangle when it's height is 6cm
2 answers:
Let
b--------> the length of the base of a triangle
h--------> the length of the height of a triangle
we know that
The area of a triangle is equal to
------> equation
if the height is
then
<u>Find the value of b</u>
substitute in the equation
<u>Find the area of the triangle</u>
therefore
<u>the answer is</u>
the area of the triangle is equal to
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Sum of all angles of a triangle is equal to 180°. Therefore,
A + B + C = 180
Given that, A = 4x, B = 3x + 1, C = 7x + 11.
Hence, we can set up an equation as following:
4x + 3x + 1 + 7x + 11 = 180
14x + 12 = 180 Combine the like terms.
14x + 12 -12 = 180 - 12 Subtract 12 from each sides.
14x = 168
Divide each sides by 14.
So, x= 12.
Now by plug in x=12 in the given expressions of A, B and C we can get the measure of eah angles of the triangle. Therefore,
A = 4x = 4(12) = 48
B= 3x + 1= 3(12) + 1 = 36 + 1 = 37
C= 7x + 11 = 7(12) + 11 = 84 + 11 =95
From the above result we can see that C is the largest angle and B is the smallest angle.
There is a relationship of a triangle which state that the largest side is opposite side of the largest angle and similarly smallest side is opposite side of the smallest angle.
Here AB is the opposite side of the largest angle C. So, AB is the largest side.
Similarly AC is the smallest side.
So, the order from shortest to longest is B: AC, BC, AB
Given length of a lap = 5/8 mile.
Number of laps Carin ran = 3 1/2 laps.
3 1/2 can be read as 3 and a half. In improper fractions, it can be written as
(3*2+1)/2 = 7/2 laps.
In order to find the total distance covered in 3 1/2 or 7/2 laps, we need to multiply length of a lap by total number of laps ran.
Therefore, total distance covered = 7/2 × 5/8.
=
Multiplying across, we get
=
=
Let us convert 35/16 into mixed fractions.
On dividing 35 by 16, we get 2 quotient and 3 remainder.
So, the mixed fraction would be 2 3/16.
Therefore, she ran 2 3/16 miles in 3 1/2 laps.
A.
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)
b.
well, the points don't look like they are on the line but they actually are (plot twist)
so
since (0,0) is on th egarph
0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx
find a and b
sub points
(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b
(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b
use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b
eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b
-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b
12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b
da equation is
c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target
(0,00
(2.6,7.9)
(4.8,12.4)
(9.7,15.1)
b.
well, the points don't look like they are on the line but they actually are (plot twist)
so
since (0,0) is on th egarph
0=a(0)²+b(0)+c
0=c
so
f(x)=ax²+bx+0 or
f(x)=ax²+bx
find a and b
sub points
(2.6,7.9)
7.9=a(2.6)²+b(2.6)
7.9=6.76a+2.6b
(4.8,12.4)
12.4=a(4.8)²+b(4.8)
12.4=23.04a+4.8b
use those 2 equations
7.9=6.76a+2.6b
12.4=23.04a+4.8b
eliminate b
multiply first equation by -4.8 and 2nd by 2.6 and add them
-37.92=-32.448a-12.48b
32.24=59.904a-12.48b +
-5.68=27.456a+0b
-5.68=27.456a
divide both sides by 27.456
(-5.68/27.456)=a
find b
12.4=23.04a+4.8b
12.4=(-130.8672/27.456)+4.8b
12.4+(130.8672/27.456)=4.8b
(12.4+(130.8672/27.456))/4.8=b
da equation is
c. the roots are found with your calculator
the roots are at x=0 and x=17.287323943662
so very close to the target but not exactly on it
if the target has a radius of 0.287323943662 or more then it will hit the target