Answer:
its the first one I think
Step-by-step explanation:
Answer:
m<4 is the measurement of 20°
and m<1 is the measurement of 33°
and in order to get 127° is to subtract 180° by 127° then that gives you 53° then you ether divide 53° by 180° or, you divide 53° in half, which gives you 33° for measurement 1™ and measurement 4™ gives you 20°
Step-by-step explanation:
Answer:
n = P/8.75
Step-by-step explanation:
Jose’s pay (P) depends on the number (n) of hours he works.
P = 8.75n Divide both sides by 8.75
n = P/8.75
=====
P = $61.25
n = 61.25/8.75
n = 7 h
Jose worked for 7 h.
Answer: B ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Step-by-step explanation:
From the given table
When x changes from 1 to 2 , value of y changes from 6 to 4
The multiplicative rate of change=![\frac{4}{6}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B6%7D%3D%5Cfrac%7B2%7D%7B3%7D)
Similarly we can check
When x changes from 2 to 3 , value of y changes from 4 to ![\frac{8}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D)
The multiplicative rate of change=![\frac{\frac{8}{3}}{4}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B8%7D%7B3%7D%7D%7B4%7D%3D%5Cfrac%7B2%7D%7B3%7D)
When x changes from 3 to 4 , value of y changes from
to ![\frac{16}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B16%7D%7B9%7D)
The multiplicative rate of change=![\frac{\frac{16}{9}}{\frac{8}{3}}=\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B16%7D%7B9%7D%7D%7B%5Cfrac%7B8%7D%7B3%7D%7D%3D%5Cfrac%7B2%7D%7B3%7D)
Therefore, the multiplicative rate of exponential function = ![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Answer:
<h2>B. 7.1</h2>
Step-by-step explanation:
Given the sample data 2 6 15 9 11 22 1 4 8 19, before we can get the standard deviation, we need to first calculate the mean.
mean = 2 +6 +15 +9 +11 +22 +1 +4 +8 +19/10
mean = 97/10
mean = 9.7
Standard deviation for ungrouped data is expressed using the formula;
![S = \sqrt{ \dfrac{\sum(x-\overline x)^2}{n-1} }](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%7B%20%5Cdfrac%7B%5Csum%28x-%5Coverline%20x%29%5E2%7D%7Bn-1%7D%20%7D)
![\overline x \ is\ the \ mean\\n \ is \ sample \ size](https://tex.z-dn.net/?f=%5Coverline%20x%20%5C%20is%5C%20the%20%5C%20mean%5C%5Cn%20%5C%20is%20%5C%20sample%20%5C%20size)
![S = \sqrt{\frac{(2-9.7)^2+(6-9.7)^2+(15-9.7)^2+(9-9.7)^2+(11-9.7)^2+(22-9.7)^2+(1-9.7)^2+(4-9.7)^2+(8-9.7)^2+(19-9.7)^2}{10-1} }\\ S = \sqrt{\frac{(-7.7)^2+(-3.7)^2+(5.3)^2+(-0.7)^2+(1.3)^2+(12.3)^2+(-8.7)^2+(-5.7)^2+(-1.7)^2+(9.3)^2}{10-1} }\\\\S = \sqrt{\dfrac{59.29+13.69+28.09+0.49+1.69+151.29+75.69+32.49+2.89+86.49}{10-1} }\\\\\\S = \sqrt{\dfrac{452.1}{9} }\\\\S = \sqrt{50.23}\\ \\S = 7.08\\\\S \approx 7.1](https://tex.z-dn.net/?f=S%20%3D%20%5Csqrt%7B%5Cfrac%7B%282-9.7%29%5E2%2B%286-9.7%29%5E2%2B%2815-9.7%29%5E2%2B%289-9.7%29%5E2%2B%2811-9.7%29%5E2%2B%2822-9.7%29%5E2%2B%281-9.7%29%5E2%2B%284-9.7%29%5E2%2B%288-9.7%29%5E2%2B%2819-9.7%29%5E2%7D%7B10-1%7D%20%7D%5C%5C%20S%20%3D%20%5Csqrt%7B%5Cfrac%7B%28-7.7%29%5E2%2B%28-3.7%29%5E2%2B%285.3%29%5E2%2B%28-0.7%29%5E2%2B%281.3%29%5E2%2B%2812.3%29%5E2%2B%28-8.7%29%5E2%2B%28-5.7%29%5E2%2B%28-1.7%29%5E2%2B%289.3%29%5E2%7D%7B10-1%7D%20%7D%5C%5C%5C%5CS%20%3D%20%20%5Csqrt%7B%5Cdfrac%7B59.29%2B13.69%2B28.09%2B0.49%2B1.69%2B151.29%2B75.69%2B32.49%2B2.89%2B86.49%7D%7B10-1%7D%20%7D%5C%5C%5C%5C%5C%5CS%20%3D%20%20%5Csqrt%7B%5Cdfrac%7B452.1%7D%7B9%7D%20%7D%5C%5C%5C%5CS%20%3D%20%5Csqrt%7B50.23%7D%5C%5C%20%5C%5CS%20%3D%207.08%5C%5C%5C%5CS%20%5Capprox%207.1)
<em>Hence the standard deviation of the sample data is 7.1</em>