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Norma-Jean [14]
4 years ago
14

You have two fair, six-sides dice. However, the dice have been modified so that instead or 1,2,3,4,5,6 the sides are numbered 1,

2,2,2,3,4.
What is the probability the total of the two dice is an even number?
Mathematics
2 answers:
Sonja [21]4 years ago
5 0

Answer:

5/9.

Step-by-step explanation:

Prob ( first  dice = 2 and second = 2) = 1/2 * 1/2 = 1/4

Prob ( first  = 2 , second = 4) = 1/2 * 1/6 = 1/12

Prob ( first = 4 and second = 2) = 1/12.

Prob ( first = 3 and second = 1 ) = 1/36

Prob ( first = 1 and second = 3) = 1/36.

Prob ( first = 3 and second = 3) = 1/6 *1/6 = 1/36.

Prob (first = 1 and second = 1 = 1/36.

Prob (first = 4 and second = 4 = 1/36.

Required probability is the sum of these which is:

5/9.

I hope I've thought of all the possible outcomes.

gogolik [260]4 years ago
3 0

Answer:

.

Step-by-step explanation:

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Varvara68 [4.7K]
You want the minimum of the solutions to
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There are many ways to solve these equations. Adding them together, you get
  8x = 40
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Since this value is less than 12, it is the smaller number. The smaller number is 5.
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3 years ago
Karen made 171 for 9 hours of work At the same rate how much would she make for 17 hours of work?
Kipish [7]

Answer:

$323

Step-by-step explanation:

Hello! First you would need to divide $171 by 9 to see how much money she makes an hour....

$171 / 9 = $19 an hour

Now that you know how much she makes an hour, multiply that amount by 17 to find out how much money she will make if she works for 17 hours.

$19 * 17 = $323

She will make $323 if she works for 17 hrs. :)

Hope this helps!

-Mikayla

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3 years ago
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A piece of brass contains 1.66 grams of copper and 0.34 gram of
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3 0
3 years ago
Please help me on this question
weeeeeb [17]

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A car is purchased for $28,000. After each year, the resale value decreases by
Dennis_Churaev [7]
\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=I(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &28000\\
r=rate\to 35\%\to \frac{35}{100}\to &0.35\\
t=\textit{elapsed time}\to &3\\
\end{cases}
\\\\\\
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\\\\\\
\textit{which rounds up to }7689
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3 years ago
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