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4 years ago

ignore selected answer haha just need help answering

Mathematics

1 answer:

masya89 [10]4 years ago

7 0

Answer:

$x^2+8x+15$

Step-by-step explanation:

$f(x)=x+4\\g(f(x))=g(x+4)\\g(x+4)=(x+4)^2-1\\(x+4)^2-1=x^2+8x+15$

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Use a transformation to solve the equation. b + 0.6 = –1

Nina [5.8K]

You answer should be :

-1.6

Hope that helped!

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3 years ago

I need help on all three questions provided I'll mark you as the brainiest and friend you.

OLEGan [10]

11. 10^-8 = 1 • 10^-8 in decimal form

12. 6 • 10^-4 = 0.0006 in decimal form

13. n^m turns into 5^4

5 • 5 • 5 • 5 = 625
5^4 = 625

3 0

3 years ago

Read 2 more answers

If j = h and k = m, then which expression represents the value of g?

Anton [14]

Answer:

g = $\frac{f}{2}$

Step-by-step explanation:

The segment DE joining the midpoints of 2 sides of the triangle is parallel to the third side and half the length of the third side, thus

g = $\frac{f}{2}$

6 0

4 years ago

Simplify powers of i. ASSIGNMENT Simplify each of the following powers of i. I^32

algol [13]

Answer:

i^15=-i

i^32=1

1^99=-i

i^22=-1

hope this helps :)

im sorry for the late answer, i put all the answers incase some one needs them, have a nice day!

Step-by-step explanation:

5 0

4 years ago

The Institute of Education Sciences measures the high school dropout rate as the percentage of 16- through 24-year-olds who are

STALIN [3.7K]

Answer:

We conclude that the proportion of dropouts has changed from the historical value of 0.081.

Step-by-step explanation:

We are given that in 2009, the high school dropout rate was 8.1%. A polling company recently took a survey of 1000 people between the ages of 16 and 24 and found 6.5% of them are high school dropouts.

The polling company would like to determine whether the proportion of dropouts has changed from the historical value of 0.081.

Let p = proportion of school dropouts rate

SO, Null Hypothesis, $H_0$ : p = 0.081 {means that the proportion of dropouts has not changed from the historical value of 0.081}

Alternate Hypothesis, $H_A$ : p $\neq$ 0.081 {means that the proportion of dropouts has changed from the historical value of 0.081}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of high school dropout rate = 6.5%

n = sample of people = 1000

So, test statistics = $\frac{0.065-0.081}{{\sqrt{\frac{0.065(1-0.065)}{1000} } } } }$

= -2.05

Also, P-value is given by the following formula;

P-value = P(Z < -2.05) = 1 - P(Z $\leq$ 2.05)

= 1 - 0.97982 = 0.0202 or 2.02%

Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test. Since our test statistics does not lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the proportion of dropouts has changed from the historical value of 0.081.

7 0

4 years ago

*ignore selected answer haha* just need help answering

ignore selected answer haha just need help answering