Point slope
y-y1=m(x-x1)
where you are given the point (x1,y1) and the slope is m
we are given the point (-3,6)
x1=-3
y1=6
y-6=m(x-(-3))
y-6=m(x+3) is the point slope form and we don't kn ow the slope yet
400g=.4kg
.4kg×25p/1kg=10p
2y² + y - 3
(2y+3)(y-1)
2y(y-1) + 3(y-1)
2y² - 2y + 3y - 3
2y² + y - 3
2y + 3 = 0
2y = -3
y = -3/2
y = -1 1/2
y - 1 = 0
y = 1
2y² + y - 3 = 0
2(-3/2)² + (-3/2) - 3 = 0
2(9/4) - 3/2 - 3 = 0
18/4 - 3/2 - 3 = 0
18/4 - (3/2 * 2/2) - 3(4/4) = 0
18/4 - 6/4 - 12/4 = 0
(18 - 6 - 12)/4 = 0
(18 -18)/4 = 0
0/4 = 0
0 = 0
Answer:
2 or 3 im not sure but choes 2
Step-by-step explanation:
Answer:
(-21, -38)
Step-by-step explanation:
Given the simultaneous equation
10x-6y = 18 ... 1
9x+6y=39 ...2
Using the Elimination method
Subtract
10x - 9x = 18 - 39
x = -21
substitute x = -21 into 1;
From 1:
10x-6y = 18
10(-21)-6y = 18
-210 - 6y = 18
-6y = 18+210
-6y = 228
y = 228/-6
y =-38
Hence the solution to the system is (-21, -38)
