<span>Option D. Total number of traffic accidents per year, by means of a bar chart that shows the difference of given values and that are represented by size, length and color. This to know the number of accidents that occur as first information. Also the option C. The decrease number of traffic accidents per year, the same with a bar chart that represents the data and its different results thrown. This is to determine the decrease, after knowing the annual number of accidents. This also helps to know the number of current accidents, increase, decrease and the main causes of accidents in large cities.</span>
Answer: the actual answer it d. y=-1/3x-5
Step-by-step explanation:
Answer:
0.12 = 12%
Step-by-step explanation:
To find this probability, we need to multiply the probability of getting route B, and the probability of getting home by 4 P.M if we choose route B.
If the probability of choosing route A is 60%, we have that the probability of choosing route B is 100% - 60% = 40%
Then, we have that the probability of getting home by 4 P.M. when choosing route B is 30%, so the final probability is:
P = 40% * 30% = 0.4 * 0.3 = 0.12 = 12%
Answer: 0.39
Step-by-step explanation:
Given the following classification :
Heavy smokers (H) = 10%
Light smokers (L) = 20%
Non smokers (N) = 70%
Given that :
The death rates of the heavy and light smokers were five and three times that of the nonsmokers, respectively
Let probability of death = D
P(D | N) = d
P(D | H) = 5d
P(D | L) = 3d
Hence,
P(D) = [P(H) * P(D | H) + P(L) * P(D | L) + P(N) * P(D | N)]
P(D) = [0.1 * 5d + 0.2 * 3d + 0.7 * d]
P(D) = [0.5d + 0.6d + 0.7d]
P(D) = 1.8d
A randomly selected participant died over the five-year period: calculate the probability that the participant was a nonsmoker.
P(N | D) = [P(N) * P(D | N)] / P(D)
P(N | D) = 0.7d / 1.8d
P(N | D) = 0.3888
= 0.39
