Complete Question
The length of the guy wire supporting a cell tower is 120 m. The guy wire is anchored to the ground at a distance of 80 m from the base of the tower to the nearest hundredth of a meter how tall is the tower?
Answer:
89.44m
Step-by-step explanation:
We solve this question using the Pythagoras Theorem
This is given as:
Hypotenuse² = Opposite ² + Adjacent ²
Hypotenuse = Length of the guy wire = 120m
Adjacent = Distance from the base of the tower = 80m
Opposite = Height of the building = x
Hence:
120² = x² + 80²
Collect like terms
x² = 120² - 80²
x = √120² - 80²
x = √(8000)
x = 89.4427191 m
Approximately the height of the tower is = 89.44m
24 cause you can only fit 24 on a backsplah
Answer:
n+4=12
n=12-4
n=8
Step-by-step explanation:
hope it helps
Answer:
17^5+17^4 = 17^4 * (17^1 + 1) = 17^4 * 18
Step-by-step explanation:
Answer:
<h2>∠HFG = 115°</h2>
Step-by-step explanation:
∠JFG + ∠HJF = 180° <em>[Adjacent angles of parallelogram are supplementary] </em>
<em>∠</em>JFG = 65°
=> 65° + ∠HJF = 180°
=> ∠HFG = 180° - 65°
=> ∠HFG = 115°