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nevsk [136]
2 years ago
10

The bars of a histogram should be shown in increasing order. true or false

Mathematics
1 answer:
attashe74 [19]2 years ago
5 0

Answer:

false it can be in any order but must be according to the set of data

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What is the rate of change of the linear function represented by the table? StartFraction one Over three EndFraction StartFracti
Lynna [10]

The rate of change of the linear function represented by the table is 3

<h3>Rate of change of a function</h3>

The rate of change of a function is also known as the slope of a function. The equation for calculating the slope is expressed as:

Slope = y2-y1/x2-x1

using the coordinates from the table (-2, -13) and (-1, -10)

Substitute

Slope = -10-(-13)/-1-(-2)

Slope = -10+13/-1+2

Slope =3

Hence the rate of change of the linear function represented by the table is 3

Learn more on rate of change here: brainly.com/question/25184007

#SPJ1

5 0
1 year ago
A regular octagon with one side 6 In.
Gwar [14]
The perimeter is 48 inches if that's what you need to know...
5 0
2 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
3 years ago
Negate the conditional statement.
Tpy6a [65]

(not <em>a</em> or not <em>b</em>) implies <em>c</em>   <==>   not (not <em>a</em> or not <em>b</em>) or <em>c</em>

so negating gives

not [(not <em>a</em> or not <em>b</em>) implies <em>c</em>]   <==>   not[ not (not <em>a</em> or not <em>b</em>) or <em>c</em>]

which we can simplify somewhat to

not (not (not <em>a</em> or not <em>b</em>)) and not <em>c</em>

(not <em>a</em> or not <em>b</em>) and not <em>c</em>

(not <em>a</em> and not <em>c</em>) or (not <em>b</em> and not <em>c</em>)

not (<em>a</em> or <em>c</em>) or not (<em>b</em> or <em>c</em>)

not ((<em>a</em> or <em>c</em>) and (<em>b</em> or <em>c</em>))

not ((<em>a</em> and <em>b</em>) or <em>c</em>)

3 0
2 years ago
Find the decimal notation for 7\9
34kurt
Hi!

This fraction converted to a decimal number is 0.7 with the 7 repeating

0.7777777777777777777777777777777777777777...
∞
8 0
3 years ago
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