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mamaluj [8]
3 years ago
6

(x+1)^2-(x-1)^2 dont kbow what to do

Mathematics
1 answer:
marshall27 [118]3 years ago
6 0

Use this formula a2 − b2 = (a + b)(a − b)

<span>(x+1)^2-(x-1)^2  in this case, a = x+1, b = x-1</span>

<span>= [(x+1) + (x-1)] *  [(x+1) – (x-1)]</span>

=(x +1 + x – 1) *(x +1 – x +1)

= 2x * 2

<span>=4x</span>

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C

Step-by-step explanation:

I got it right on Edge.

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What is the distance between the points (-12, 11) and (-18, 17), to the<br> nearest tenth? *
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Answer:

8.5 units

Step-by-step explanation:

The distance between two points is given by

d=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Taking points (-12, 11) and (-18, 17) as the first and second points respectively then

d=\sqrt{(-18--12)^{2}+(17-11)^{2}}

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Val buys a computer for $720. If this is 120% of what the store paid for the
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The answer to this question is 120
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Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
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Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

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