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butalik [34]
3 years ago
5

Plz help me find these functions!

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

\sin \alpha = \frac{5}{13}, \cos \alpha = \frac{12}{13}, \tan \alpha = \frac{5}{12}, \cot \alpha = \frac{12}{5}, \sec \alpha = \frac{13}{12}, \csc \alpha = \frac{13}{5}

Step-by-step explanation:

The angle \alpha is the angle opposite to the side of length 5 and adjacent to the side of length 12. From Trigonometry we remember the following relationships:

\sin \alpha = \frac{5}{\sqrt{5^{2}+12^{2}}}

\sin \alpha = \frac{5}{13}

\cos \alpha = \frac{12}{\sqrt{5^{2}+12^{2}}}

\cos \alpha = \frac{12}{13}

\tan \alpha = \frac{5}{12}

\cot \alpha = \frac{12}{5}

\sec \alpha = \frac{\sqrt{5^{2}+12^{2}}}{12}

\sec \alpha = \frac{13}{12}

\csc \alpha = \frac{\sqrt{5^{2}+12^{2}}}{5}

\csc \alpha = \frac{13}{5}

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