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butalik [34]
3 years ago
5

Plz help me find these functions!

Mathematics
1 answer:
Iteru [2.4K]3 years ago
4 0

Answer:

\sin \alpha = \frac{5}{13}, \cos \alpha = \frac{12}{13}, \tan \alpha = \frac{5}{12}, \cot \alpha = \frac{12}{5}, \sec \alpha = \frac{13}{12}, \csc \alpha = \frac{13}{5}

Step-by-step explanation:

The angle \alpha is the angle opposite to the side of length 5 and adjacent to the side of length 12. From Trigonometry we remember the following relationships:

\sin \alpha = \frac{5}{\sqrt{5^{2}+12^{2}}}

\sin \alpha = \frac{5}{13}

\cos \alpha = \frac{12}{\sqrt{5^{2}+12^{2}}}

\cos \alpha = \frac{12}{13}

\tan \alpha = \frac{5}{12}

\cot \alpha = \frac{12}{5}

\sec \alpha = \frac{\sqrt{5^{2}+12^{2}}}{12}

\sec \alpha = \frac{13}{12}

\csc \alpha = \frac{\sqrt{5^{2}+12^{2}}}{5}

\csc \alpha = \frac{13}{5}

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If an x-coordinate repeats, can a relation still be a function?<br><br>I need help right now
Gre4nikov [31]

Answer:

No

Step-by-step explanation:

if you see any duplicates or repetitions in the x-values, the relation is not a function.

8 0
3 years ago
The answer choices are <br><br> A) 60<br> B)108<br> C)72<br> D)54
madreJ [45]
If you subtract 180 from <1 which is 6 then subtract again to <12 your should get B
7 0
3 years ago
Each year about 1500 students take the introductory statistics course at a large university. This year scores on the final exam
Luba_88 [7]

Answer:

a. Left Skewed

b. More students scored above 70

c. No

d. 0.0008

e. standard deviation increases by 1.4142

Step-by-step explanation:

a. The distribution  is Left skewed. The maximum possible score is 100 and the mean is 70, hence, there is a barrier preventing a long right tail.

-The scores to the left is only 20, the left therefore is longer.

-The median, 74, is higher than the mean, 70, thus the mean is more left leaning.

b.More students will score more than 70.

-the median is 74 suggesting that 50% plus have scored 74points +

- Given the mean is 70 points, it's therefore obvious that more than 50% of the students have score more than 70 points.

c. No. This is not a normal distribution therefore we cannot calculate the probability that a randomly chosen student scored above 75 using this distribution.

d. The sample size  n is large, n>30, so we can use the central limit theorem to approximate the probability:

Standard \ Error=\frac{\sigma}{\sqrt{n}}\\\\=\frac{10}{\sqrt{40}}\\\\=1.5811\\\\z=\frac{75-70}{1.5811}\\\\=3.1623\\\\\\(PX>70)=P(z>3.1623)\\\\=0.0008\\

e. The standard deviation will increase by the square root of the decreament :

\sqrt{2}=1.4142

#Standard deviation increases by 1.4142

3 0
4 years ago
Please find the answer , it is a very importatnt question
Anna [14]

Step-by-step explanation:

The given expression is :

\dfrac{2-\sqrt5}{2+3\sqrt5}=\sqrt5 x+y ....(1)

Taking LHS of the above expression

\dfrac{2-\sqrt5}{2+3\sqrt5}

Rationalizing both denominator and numerator.

\dfrac{2-\sqrt5}{2+3\sqrt5}\times \dfrac{2-3\sqrt5}{2-3\sqrt5}=\dfrac{4-6\sqrt5-2\sqrt5+15}{2^2-(3\sqrt5)^2}\\\\=\dfrac{19-8\sqrt5}{4-45}\\\\=\dfrac{19-8\sqrt5}{-41}\\\\=\dfrac{\sqrt5 \times 8}{41}+(\dfrac{-19}{41})

Equation (1) becomes,

\dfrac{\sqrt5 \times 8}{41}+(\dfrac{-19}{41})=\sqrt 5\ x+y

Equating both sides,

x=\dfrac{8}{41} and y=\dfrac{-19}{41}

Hence, this is the required solution.

7 0
3 years ago
Irections: Simplify each expressio<br> 25-(√16-1)-(3-9)²
enyata [817]

Answer:

-14

Step-by-step explanation:

\sqrt{16} = 4\\\\(\sqrt{16} - 1) = (4 -1) =3\\\\(3-9) = (-6)\\\\(3-9) ^2 = (-6)^2 = 36\\\\25 -  3 - 36 = 25 - 39 =  -14\\

3 0
2 years ago
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