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3 years ago

12

What is the sum?

B4%7D%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20" id="TexFormula1" title=" \frac{2}{ {x}^{2} } + \frac{4}{ {x}^{2} } " alt=" \frac{2}{ {x}^{2} } + \frac{4}{ {x}^{2} } " align="absmiddle" class="latex-formula">

2 answers:

shutvik [7]3 years ago

8 0

Answer:

6/x^2

Step-by-step explanation:

Simplify the following:

2/x^2 + 4/x^2

2/x^2 + 4/x^2 = (2 + 4)/x^2:

(2 + 4)/x^2

2 + 4 = 6:

Answer: 6/x^2

sveta [45]3 years ago

7 0

Answer:

6/x²

Step-by-step explanation:

$\frac{2}{x^{2} } + \frac{4}{x^{2} } \\\\$

= (2+4) / x²

= 6/x²

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Design a sine function with the given properties:

Rom4ik [11]

Answer:

$f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$ .

Step-by-step explanation:

Given information:

Period = 24 hr

Maximum = 16 at t=16 hr.

Minimum = 10 at t=4 hr.

The general sin function is

$y=A+\sin(B(x-C))+D$ .... (1)

where, |A| is altitude, $\frac{2\pi}{B}$ is period, C is phase shift and D is midline.

Period is 24 hr.

$24=\dfrac{2\pi}{B}\Rightarrow B=\dfrac{\pi}{12}$

Altitude is

$A=\dfrac{Maximum-Minimum}{2}=\dfrac{16-10}{2}=3$

$D=\dfrac{Maximum+Minimum}{2}=\dfrac{16+10}{2}=13$

The function is minimum at t=4 and maximum at t=16,phase shift is

$C=\dfrac{16+4}{2}=10$

Substitute these values in equation (1).

$y=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$

Therefore, the required function is $f(x)=3\sin\left(\frac{\pi}{12}\left(x-10\right)\right)+13$ .

8 0

3 years ago

What is -2 2/3 divide by -1/2

tamaranim1 [39]

Answer:

16/3

Step-by-step explanation:

8 0

3 years ago

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What is reflexive property

bixtya [17]

The reflexive property of equality simply states that a value is equal to itself.

5 0

4 years ago

Two decimals numbers, to the thousandths, that have a sum of about 5 and a difference of about 3. Then do the math to prove it w

mina [271]

Answer:

The numbers are approximately: 4.000 and 1.000

Step-by-step explanation:

The given parameters can be expressed as:

$\frac{x}{1000} + \frac{y}{1000} \approx 5$

$\frac{x}{1000} - \frac{y}{1000} \approx 3$

Required

Determine the numbers

In each of the equations, multiply by 1000

$1000 * [\frac{x}{1000} + \frac{y}{1000} \approx 5]$

$x + y \approx 5000$

$1000 * [\frac{x}{1000} - \frac{y}{1000} \approx 3]$

$x-y \approx 3000$

So, we have:

$x + y \approx 5000$

$x-y \approx 3000$

Add the two equations

$x + x + y - y \approx 5000 + 3000$

$2x \approx 8000$

Solve for x

$x \approx 8000/2$

$x \approx 4000$

Substitute $x \approx 4000$ in $x + y \approx 5000$

$4000 + y \approx 5000$

$y \approx 5000 - 4000$

$y \approx 1000$

Using:

$\frac{x}{1000} + \frac{y}{1000} \approx 5$

We have:

$\frac{4000}{1000} + \frac{1000}{1000} \approx 5$

$4.000 + 1.000 \approx5$

<em>This implies that, the numbers approximates to 4.000 and 1.000, respectively.</em>

4 0

3 years ago

7, 13, 19, 25, 31, 37 <br> how much is this increasing by?

Allisa [31]

They increase by 6, how you find that out is by subtracting the second by the first, and the third by the second

6 0

3 years ago

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