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Naddika [18.5K]
3 years ago
11

Make a function table for each situation. The find the domain and range.

Mathematics
1 answer:
kupik [55]3 years ago
8 0
For the first hour its 24, then 48, then 72, then 100!!!
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N<br><img src="https://tex.z-dn.net/?f=n%20%2B%207%20%5Cgeqslant%2010" id="TexFormula1" title="n + 7 \geqslant 10" alt="n + 7 \g
lutik1710 [3]

n \geqslant 3
3 0
3 years ago
The solution for a system of two linear equations is (0, 0). Which equation below could be one of the equations in the system? A
earnstyle [38]

Answer:

y = -3x

Step-by-step explanation:

For the equation to be a part of a system, the point (0,0) must be a part of the line. Since y = -3x is proportional meaning b = 0, its y-intercept is (0,0). This means it must cross through and include (0,0). This is a part of the system.

4 0
3 years ago
What percent of 40 is 14?
Lemur [1.5K]

First translate the question into an equation.

"What percent" means x/100, "of 40" means times 40, "is 14" equals 14.

So we have (x)(40) = 14 or 40x = 14.

Dividing both sides by 40, we find that x = 0.35.

Now, we want to write our answer as a percent.

So we move the decimal 2 places to the right and we have 35%.

3 0
3 years ago
A box contains three plain pencils and 5 pens. A second box contains three colored pencils and three crayons. One item from each
worty [1.4K]

Answer:

Therefore the probability that a pen from the first box and a crayon from the second box are selected is \frac5{16}

Step-by-step explanation:

Probability:

The ratio of the number of favorable outcomes to the number all possible outcomes of the event.

Probability=\frac{\textrm{The number favorable outcomes}}{\textrm{The number all possible}}

Given that,

Three plain pencils and 5 pens are contained by the first box.

Total number of pens and pencils is =(3+5)=8

The probability that a pen is selected from the first box is

=P(A)

=\frac{\textrm{The number pens}}{\textrm{Total number of pens and pencils}}

=\frac{5}{8}

A second box contains three colored pencils and three crayons.

Total number of pencils and crayons is =(3+3)=6

The probability that a crayon is selected from the second box is

=P(B)

=\frac{\textrm{The number of crayon}}{\textrm{Total number of crayons and pencils}}

=\frac{3}{6}

Since both events are mutually independent.

The required probability is multiple of the events

Therefore the required probability is

=\frac58\times \frac36

=\frac5{16}

4 0
3 years ago
Can someone please help me with the last 3
mash [69]

Answer:

its pretty complicated

Step-by-step explanation:

4 0
3 years ago
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