Answer:
The attachment shows ΔBAC ~ ΔBDA
Step-by-step explanation:
You want segment AB to be part of two similar, but not congruent, triangles. One way to do that is to make AB the hypotenuse of one triangle and the leg of another.
It is convenient to construct these triangles using point M as the arbitrary midpoint of the hypotenuse of the larger triangle. (We don't know the coordinates of M—we just know it is on the perpendicular bisector of AB.) BC is a diameter of circle M, and AD is the altitude of ΔABC.
A) the slope of the line: -5/11
b) the perpendicular slope of the line: 11/5
Answer:
38.5°
Step-by-step explanation:
Given that the height of the building is 8 yard and the distance between Jonathan and the building is 10 yards.
The sun is at the top of the building, let the distance between Jonathan laying on the ground and the top of the building be x. Using Pythagoras:
x² = 10² + 8²
x² = 100 + 64
x² = 164
x = √164 = 12.86 yards
For a triangle with sides a, b, c and their respective opposite angles A, B, and C. The sine rule is given as:
Let the angle that the sunlight hit the ground be y°. The andle between the building and the ground is 90°. Therefore using sine rule:
N=11
FG=16
Because N+5=2N-6
