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xxMikexx [17]
3 years ago
15

Factorise(x + 2)^2 + p^2 + 2p (x + 2)​

Mathematics
1 answer:
Sveta_85 [38]3 years ago
8 0

Answer:

( x +2 +p) ( x+2+p)

Step-by-step explanation:

let x+2 be x

x^2 + p^2 + 2px

x^2 + 2 × p × x + p^2

(x+p)^2

(x+p)(x+p)

replacing the value of x

( x +2 +p) ( x+2+p)

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What are the coordinates of Jefferson High Schools courtyard
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A 150-unit apartment complex is infested with rats. The apartment caretaker checked 9 units and found the following number of ra
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3 years ago
(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounde
monitta

Using the distance formula, d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth?

Using the points given, plug them into the equation.

d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2  } \\d = \sqrt{((4) - (-2))^2 + ((4) - (2)^2  } \\d=\sqrt{(4+2)^2 + (4-2)^2}\\d=\sqrt{(6)^2 + (2)^2}  \\d=\sqrt{36+4} \\d=\sqrt{40} \\

Plug this into a calculator and you get 6.32455532

Since you only need it up to the tenth (0.1), round up 6.32

<em>Five or more, let it soar. Four or less, let it rest.</em>

Since two is lower than four, we drop it.

Therefore, the distance between points (-2, 2) and (4, 4) is 6.3

Hope this helps ^w^

8 0
2 years ago
The graph of
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Answer:

Positive and negative intervals on a graph

Step-by-step explanation:

The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero). The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). hope this helps you :)

3 0
3 years ago
Read 2 more answers
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