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2 years ago

Need help, please, please.

Mathematics

1 answer:

Ber [7]2 years ago

3 0

-66 is the 27th term.

You have a function in terms of n. Recall that n is the nth term in the sequence.
Substitute n = 27 into the equation to find the 27th term.

a₂₇ = -10 + (27 + 1)(-2) = -10 + (28)(-2) = -10 - 56 = -66

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There was 2/3 of a pan of a lasagna in the refrigerator. Bill and his friends ate half of what was left. Write a number sentence

olga nikolaevna [1]

Bill and his friends ate 1/3 of the pan, you get this by doing: 2/3 / 1/2 = 1/3 or 0.3333

7 0

2 years ago

X + 2y = 10<br> 3x + 4y = 8<br><br> Which point is the solution to the system of equations?

bija089 [108]

Answer:

x = -12

y = 11

Step-by-step explanation:

i used substitution and let 'x' = 10 - 2y

3(10 - 2y) + 4y = 8

30 - 6y + 4y = 8

30 -2y = 8

-2y = -22

y = 11

x + 2(11) = 10

x + 22 = 10

x = -12

6 0

2 years ago

Write a quadratic function for each graph described.

user100 [1]

Answer:

$y=2x^2-\frac{4}{3}x-\frac{10}{3}$

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

we can write the equation of the parabola as

$y=a(x+1)(x-\frac{5}{3})$

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

$40=a(5+1)(5-\frac{5}{3})$

$40=a(6)(\frac{10}{3})$

$40=20a\\a=2$

substitute

$y=2(x+1)(x-\frac{5}{3})$

apply distributive property

$y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}$

see the attached figure to better understand the problem

6 0

2 years ago

Y = -5x + 15 2x + y = 12

Nana76 [90]

Answer:

x = 1, y = 10

Step-by-step explanation:

y = -5x + 15 --- Equation 1

2x + y = 12 --- Equation 2

Substitute y = -5x + 15 into Equation 2:

2x + y = 12

2x - 5x + 15 = 12

Evaluate like terms.

15 - 3x = 12

Isolate -3x.

-3x = 12 - 15

Evaluate like terms.

-3x = -3

Find x.

x = -3 ÷ -3

x = 1

Substitute x = 1 into Equation 2:

2x + y = 12

2(1) + y = 12

2 + y = 12

Isolate y.

y = 12 - 2

y = 10

4 0

2 years ago

Read 2 more answers

Simplify: 18q2−45q+25/9q2−25.

Svet_ta [14]

Answer:

$\frac{(6q-5)}{(3q+5)}$

Step-by-step explanation:

Given: $\frac{18q^{2}-45q+25 }{9q^{2}-25 }$

Factorizing the numerator and the denominator, we have:

18 $q^{2}$ - 45q + 25 = 18 $q^{2}$ - 30q - 15q + 25

= (3q - 5)(6q - 5)

and

9 $q^{2}$ - 25 = (3q - 5)(3q + 5)

So that,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(3q-5)(6q-5)}{(3q-5)(3q+5)}$

= $\frac{(6q-5)}{(3q+5)}$

Therefore,

$\frac{18q^{2}-45q+25 }{9q^{2}-25 }$ = $\frac{(6q-5)}{(3q+5)}$

5 0

2 years ago