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NNADVOKAT [17]
2 years ago
11

HELP PLEASE 50 points !!! Given a polynomial function describe the effects on the Y intercept, region where the graph is incre

asing and decreasing in the end behavior when the following changes are made make sure to account for even and odd functions
When f(x) becomes -f(x)+ 2
When f(x) becomes f(x+3)
Mathematics
1 answer:
Gwar [14]2 years ago
6 0

Even function:

A function is said to be even if its graph is symmetric with respect to the , that is:

Odd function:

A function is said to be odd if its graph is symmetric with respect to the origin, that is:

So let's analyze each question for each type of functions using examples of polynomial functions. Thus:

FOR EVEN FUNCTIONS:

1. When  becomes  

1.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

We know that the graph  intersects the y-axis when , therefore:

So:

So the y-intercept of  is one unit less than the y-intercept of

1.2. Effects on the regions where the graph is increasing and decreasing

Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function  increases and decreases in the same intervals of

1.3 The end behavior when the following changes are made.

The function is shifted one unit downward, so each point of  has the same x-coordinate but the output is one unit less than the output of . Thus, each point will be sketched as:

FOR ODD FUNCTIONS:

2. When  becomes  

2.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is one unit less. So the graph is shifted one unit downward again.

An example is shown in Figure 1. The graph in blue is the function:

and the function in red is:

So you can see that:

2.2. Effects on the regions where the graph is increasing and decreasing

The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of

In Figure 1 you can see that both functions increase at:

and decrease at:

2.3 The end behavior when the following changes are made.

It happens the same, the output is one unit less than the output of . So, you can write the points just as they were written before.

So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.

FOR EVEN FUNCTIONS:

3. When  becomes  

3.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

As we know, the graph  intersects the y-axis when , therefore:

And:

So the new y-intercept is the negative of the previous intercept shifted one unit upward.

3.2. Effects on the regions where the graph is increasing and decreasing

In the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

3.3 The end behavior when the following changes are made.

Each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward, that is:

FOR ODD FUNCTIONS:

4. When  becomes  

4.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept shifted one unit upward.

4.2. Effects on the regions where the graph is increasing and decreasing

In this case it happens the same. So in the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

4.3 The end behavior when the following changes are made.

Similarly, each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward.

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777dan777 [17]

Answer: (2,2) and (-5,16)

Step-by-step explanation:

Here we have both Line (Linear Function) and Parabola (Quadratic Function)

So I am gonna write these equations here,

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The first equation has Parabola graph (Since it's second degree.)

and the second equation has line graph.

To find the intersection, you have to substitute either -2x+6 in first equation (Quadratic) or x^2+x-4 in second equation (Linear)

For me, I am going to substitute x^2+x-4 in y=-2x+6.

x^2+x-4=-2x+6

Now solve the equation and find the value of x.

Since it's Quadratic Equation (Because there's x^2) I'd move -2x+6 to the left side.

x^2+x-4+2x-6=0 Finish things here (Subtract and Addition)

x^2+3x-10=0 What two numbers multiply to 10? Find the factors of 10, that are [1 and 10] and [2 and 5]

Now think about it, do you think that if 1 and 10 subtract or even addition, do you think that it'd be 3? No, of course not.

So 2 and 5 is right.

(x-2)(x+5)=0 (5-2 = 3) and (5*(-2) = -10)

Then we get both x, x=2,-5

However, this is not it. You have to substitute both x in Linear Equation.

Substitute x = 2 in y=-2x+6

y=-2(2)+6\\y=-4+6\\y=2

Order = (2,2)

Then substitute x = -5 in y=-2x+6

y=-2(-5)+6\\y=10+6\\y=16

Order = (-5,16)

So the intersections are both (2,2) and (-5,16) as shown in graph below.

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Answer:

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Step-by-step explanation:

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Vlad1618 [11]

Answer:

y = 7x - 13

Step-by-step explanation:

The equation of a line in slope- intercept form is

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with slope m = 7

Parallel lines have equal slopes, thus

y = 7x + c ← is the partial equation

To find c substitute (5, 22) into the partial equation

22 = 35 + c ⇒ c = 22 - 35 = - 13

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n200080 [17]

Answer:

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